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3 years ago

Given the reaction: 4A1 + 302 - 2A1,O, How many grams of Al will be

Chemistry

1 answer:

dlinn [17]3 years ago

4 0

Answer:

The answer to your question is 27 g of Al

Explanation:

Data

mass of Al = ?

moles of Al₂O₃ = 0.5

The correct formula for the product is Al₂O₃

Balanced chemical reaction

4Al + 3O₂ ⇒ 2Al₂O₃

Process

1.- Calculate the molar mass of the product

Al₂O₃ = (27 x 2) + (16 x 3)

= 54 + 48

= 102 g

2.- Convert the moles of Al₂O₃ to grams

102 g ---------------- 1 mol

x ---------------- 0.5 moles

x = (0.5 x 102) / 1

x = 51 g of Al₂O₃

3.- Use proportions to calculate the mass of Al

4(27) g of Al --------------- 2(102) g of Al₂O₃

x --------------- 51 g

x = (51 x 4(27)) / 2(102)

x = 5508 / 204

x = 27 g of Al

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Answer:

The anion of the compound is b CH3COO-

Explanation:

The compound cupric acetate Cu(CH3COO)2 undergo dissociation to form cupric ion Cu2+ and Acetate anion(CH3COO-)

Cu(CH3COO)2⇒ Cu2+ + CH3COO-

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3 years ago

So2−3(aq)→so2−4(aq) (basic solution) express your answer as a chemical equation. identify all of the phases in your answer. so32

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Answer:

$SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}$

Explanation:

The given reaction is an example of oxidation reaction. The step-by-step balancing procedure has been shown below:

Chemical equation: $SO_{3}^{2-}(aq.)\rightarrow SO_{4}^{2-}(aq.)$

Balance H and O in basic medium: $SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)$

Balance charge: $SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}$

Balanced chemical equation:

$SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}$

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3 years ago

How would you classify the following events?

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Chemical change is a change in which there is a change in chemical composition and there might or might not be a phase change.

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3 years ago

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Answer:

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2 years ago

Read 2 more answers

If the caffeine concentration in a particular brand of soda is 3.55 mg/oz, drinking how many cans of soda would be lethal? Assum

monitta

Answer:

The answer to your question is: 234.7 cans

Explanation:

data

caffeine concentration = 3.55 mg/oz

10.0 g of caffeine is lethal

there are 12 oz of caffeine in a can

Then

3.55 mg ----------------- 1 oz

x mg -----------------12 oz (in a can)

x = 42.6 mg of caffeine in a can

Convert it to grams 42,6 mg = 0.0426 g of caffeine in a can

Finally

0.0426 g of caffeine ------------------ 1 can

10 g of caffeine ----------------- x

x = 10 x 1/0.0436 = 234.7 cans

6 0

3 years ago