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MrRa [10]
4 years ago
6

1. Three different observers measure the melting point of a substance and agree on the

Chemistry
1 answer:
Naddik [55]4 years ago
7 0

d. precise but not accurte

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Joseph Proust showed that when elements combine to form new substances, they do so in specific mass ratios.a) trueb) false
olga55 [171]

Answer: option A) True

Explanation:

Joseph Proust is the founder of the Law of Definite proportion. This law states that two elements will always combine together to form a chemical compound and this will be in the same proportion by mass.

For Example: 2 moles of Hydrogen (H2) ALWAYS combine with 1 atom of Oxygen (O) to yield water (H2O)

So, the answer is True

3 0
3 years ago
A soccer player practices kicking the ball into the goal from halfway down the field the time it takes for the ball to get to th
Nataliya [291]
Velocity = 15 m/s

90/2 = 45 m
45/3 (seconds to reach) = 15 m 



5 0
3 years ago
Read 2 more answers
Which of the following substances has the highest melting point?
Aleksandr [31]

Nonane (b) has the highest melting point.

-----------------------------

A caveat: I'm assuming that we're dealing with the straight-chain isomers of these alkanes (specifically pentane and nonane). The straight-chain isomer of pentane (<em>n</em>-pentane, CH3-[CH2]3-CH3) has a melting point of -129.8 °C; the straight-chain isomer of nonane (<em>n-</em>nonane, CH3-[CH2]7-CH3) has a melting point of -53.5 °C. The pattern holds as you go down (or up): The more carbon atoms, the higher the melting point. So, in decreasing order of melting points here, you'd have the following: nonane > pentane > butane > ethane.

However, one structural isomer of pentane, neopentane, has a melting point of -16.4 °C, which is <em>higher </em>that the melting point of <em>n</em>-nonane despite neopentane having the same molecular formula as its straight-chain isomer. Of course, you're not to blame for coming up with this question; this is just some extra info to keep in mind.

5 0
3 years ago
How many grams of water vapor (H2O) are in a 10.2-liter sample at 0.98 atmospheres and 26°C?
diamong [38]
Hey there! 

<span>Use the equation of Clapeyron:
</span>
T in kelvin :

26 + 273.15 => 299.15 K

R = 0.082

V = 10.2 L

P = 0.98 atm

number of moles :

P *V = n * R * T

0.98 * 10.2 =  n * 0.082 * 299.15

9.996 = n * 24.5303

n = 9.996 / 24.5303

n = 0.4074 moles

Therefore:

Molar mass H2O = 18.01 g/mol

1 mole H2O ------------- 18.01 g
0.4074  moles ----------- m

m = 0.4074 * 18.01 / 1

m = 7.339 g of H2O
5 0
3 years ago
1. How do aquatic animals obtain oxygen?
Ilya [14]

Answer:

the second one filter for dissolved

Explanation:

3 0
3 years ago
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