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Temka [501]
3 years ago
11

A soccer ball is kicked from point Pi at an angle above a horizontal field. The ball follows an ideal path before landing on the

field at point Pf . Which of the following statements is true when the ball is at point X?
A. The horizontal velocity vector points to the right & equals v cos θ.
B. The vertical velocity points up & equals v sin θ.
C. The acceleration vector points up.
D. The total velocity equals the initial velocity v.
Physics
1 answer:
Nutka1998 [239]3 years ago
8 0

Answer:

A. The horizontal velocity vector points to the right & equals v cos θ.

Explanation:

The motion describes a parabolic path, where the horizontal speed is constant and the horizontal velocity vector always points to the right and equals v*cos θ.

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A neutron in a nuclear reactor makes an elastic head-on collision with the nucleus of a plutonium atom initially at rest. (a) Wh
olga55 [171]

Answer:

Fraction = 59049/60025

Explanation:

Let m be the mass of the neutron and M be the mass of the plutonium nucleus (at rest)

Now, formula for kinetic energy before collision is;

K_i = ½mu²

Formula for kinetic energy after collision is;

K_f = ½mv²

Where;

u is the velocity of the neutron before collision

v is the velocity of the neutron after collision.

From collision principle where momentum before collision equals momentum after collision, we can say that;

(m - M)u = (m + M)v

Thus,

v = [(m - M)u]/(m + M)

Putting [(m - M)u]/(m + M) for v in the final kinetic energy equation gives;

K_f = ½m([(m - M)u]/(m + M))²

K_f = ½mu²((m - M)²/(m + M)²)

To get the fraction of the neutron's kinetic energy is transferred to the plutonium nucleus, it is simply;

K_f/K_i = [½mu²((m - M)²/(m + M)²)]/½mu²

This gives;

K_f/K_i = ((m - M)²/(m + M)²)

But mass of plutonium = 244m

Thus;

K_f/K_i = ((m - 244m)²/(m + 244m)²)

K_f/K_i = 59049m²/60025m²

K_f/K_i = 59049/60025

4 0
3 years ago
What happens to the piece of steel?
anyanavicka [17]
The answer should be c....
6 0
4 years ago
Read 2 more answers
Темирказык жулдызынын жулдыздык шамасы 2,02, ал Веганын жулдыздык шамасы 0,03. Осылардын кайсысы жарык жане неше есе жарык?
miv72 [106K]

Temirkazık ruled Myanmar value of about 2.02, Vega Funny 0.03. What is the orange light which of these factors times the light?

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7 0
3 years ago
For each of the following velocity vectors, give the vector component, the scalar component, and the magnitude. (a) v = 48.0j m/
Oduvanchick [21]

Obtaining the component part of the letter 'i' warns that it is the velocity is oriented on the X axis. At the same time the numeric part, in this particular case will represent the scalar part and therefore the magnitude of the vector.

The velocity is

\vec{v} = 48.0\hat{i} \text{ m/s }

The vector component of the velocity is

v_x = 48.0m/s

The scalar component of the velocity is

v = 48.0m/s

The magnitude of the velocity is

v = 48.0m/s

3 0
4 years ago
A 750-kg automobile is moving at 26.2 m/s at a height of 5.00 m above the bottom of a hill when it runs out of gasoline. The car
Kisachek [45]

To solve this problem it is necessary to apply to the concepts related to energy conservation. For this purpose we will consider potential energy and kinetic energy as the energies linked to the body. The final kinetic energy is null since everything is converted into potential energy, therefore

Potential Energy can be defined as,

PE = mgh

Kinetic Energy can be defined as,

K= \frac{1}{2} mv^2

Now for Conservation of Energy,

KE_i+PE_i = PE_f

\frac{1}{2}mv_i^2+mgh_1 = mgh_2

\frac{1}{2} (750kg) (26.2m/s)^2 + (750)(9.8)(5) = (750)(9.8)h_2

h_2 = 40.0224m

Therefore the highets position the car reaches above the bottom of the hill is 40.02m

6 0
4 years ago
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