To develop this problem we will apply the concepts related to angular kinematic movement, related to linear kinematic movement. Linear velocity can be described in terms of angular velocity as shown below,
Here,
v = Lineal velocity
= Angular velocity
r = Radius
Our values are
Replacing to find the angular velocity we have,
Convert the units to RPM we have that
Therefore the angular speed of the wheels when the scooter is moving forward at 6.00 m/s is 955.41rpm
We can use the ideal gas equation which is expressed as PV = nRT. At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:
T1/P1 = T2/P2
P2 = T2 x P1 / T1
P2 = 273 x 340 / 713
<span>P2 = 130 kPa</span>
Scientific Notation: 4.580 x 10^-4
Scientific e Notation: 4.580e-4
Answer:
Explanation:
Initial angular speed of the ferris wheel is given as
final angular speed after friction is given as
now angular acceleration is given as
now torque due to friction on the wheel is given as
Now the power required to rotate it with initial given speed is
Answer:
a=4,32m/s^2
Explanation:
Fnet = F1 - F2
= 12-1.2
= 10.8N
m=2.5kg
Fnet =ma
10.8=2.5a then divide both sides by 2.5 to get acceleration
