Question

What is the final velocity, in meters per second, of a freight train that accelerates at a rate of 0.085 m/s2 for 7.5 min, starting with an initial velocity of 3.4 m/s

Answer 1

Answer:

$v_f=41.65\frac{m}{s}$

Explanation:

The final velocity is given by the following kinematic equation:

$v_f=v_0+at$

Here, $v_0$ is the initial velocity, a is the body's acceleration and t is the motion time. We have to convert the time to seconds:

$7.5min*\frac{60s}{1min}=450s$

Now, we calculate the final velocity:

$v_f=3.4\frac{m}{s}+(0.085\frac{m}{s^2}(450s))\\v_f=41.65\frac{m}{s}$