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Andreyy89
1 year ago
12

Why Study Science? Help me out

Physics
2 answers:
Mashutka [201]1 year ago
6 0
All but the last one!
faust18 [17]1 year ago
3 0
All of the above should be the correct answer
You might be interested in
I need help on these 3 questions plz 20 points
Dmitry_Shevchenko [17]

Answer: the first one is speed

the second one is acceleration

the last is velocity

Explanation:

i got you

4 0
3 years ago
A speedboat moving at 28 m/s approaches a no-wake buoy marker 91 m ahead. The pilot slows the boat with a constant acceleration
Tpy6a [65]

Answer:

7.5 m/s

Explanation:

We can find its velocity when it reaches the buoy by applying one of Newton's equations of motion:

v^2 = u^2 + 2as

where v = final velocity

u = initial velocity

a = acceleration

s = distance traveled

From the question:

u = 28 m/s

a = -4 m/s^2

s = 91 m

Therefore:

v^2 = 28^2 + 2 * (-4) * 91\\\\v^2 = 784 + -728 = 56\\\\v = \sqrt{56}\\ \\v = 7.5 m/s

The velocity of the boat when it reaches the buoy is 7.5 m/s.

6 0
2 years ago
True or false? When two objects interact, both force and motion are caused.​
Alla [95]
The answer to this question is true
7 0
2 years ago
A train pulls the boxcars. What are the vertical forces present? (1 point)
Greeley [361]

The vertical forces present in a boxcars being pulled by a train are weight and pull of air on the boxcars.

The forces exerted on an object can be resolved into <em>horizontal</em> and <em>vertical components.</em>

<em />

The horizontal components of the forces on an object being pulled include the following;

  • The frictional force on the object; which tends to reduce the motion,
  • force dragging the object forward
  • if the object is inclined to an angle, the horizontal component of the weight

This horizontal force is written as;

\Sigma F_x = 0\\\\F_x - F_k = ma

The vertical component of the force on the object include the following;

  • the weight of the object acting downwards
  • the pull of air on the object acting upwards

The vertical force on the object is written as;

\Sigma F_n = 0\\\\F_n - W = 0

Thus, the vertical forces present in a boxcars being pulled by a train are weight and pull of air on the boxcars.

Learn more here: brainly.com/question/2000189

5 0
2 years ago
Solve the problems. Show all work, be SI units for force for weight) .
Sav [38]

Answer:

1. 75 N

2. 6.8351 N

3. 700 N

Explanation:

1. Determination of the weight of the bowling ball:

Mass (m) = 7.5 kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

Weight = mass × acceleration due to gravity

W = m × g

W = 7.5 × 10

W = 75 N

2. Determination of the weight of the object.

Mass (m) = 683.51 g

Weight (W) =?

We'll begin by converting 683.51 g to kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

683.51 g = 683.51 g × 1 Kg / 1000 g

683.51 g = 0.68351 Kg

Thus, 683.51 g is equivalent to 0.68351 Kg.

Finally, we shall determine the weight of the object as follow:

Mass (m) = 0.68351 Kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

Weight = mass × acceleration due to gravity

W = m × g

W = 0.68351 × 10

W = 6.8351 N

3. Determination of the weight of the KHS student.

Mass (m) = 154 lb

Weight (W) =?

We'll begin by converting 154 lb to Kg. This can be obtained as follow:

2.2 lb = 1 Kg

Therefore,

154 lb = 154 lb × 1 Kg / 2.2 lb

154 lb = 70 kg

Thus, 154 lb is equivalent to 70 kg.

Finally, we shall determine the weight of the KHS student as follow:

Mass (m) = 70 Kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

Weight = mass × acceleration due to gravity

W = m × g

W = 70 × 10

W = 700 N

8 0
2 years ago
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