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4 years ago

Which of the following is true of an adiabatic process?

Physics

2 answers:

Fiesta28 [93]4 years ago

8 0

The answers are A,B,and D. APEX

poizon [28]4 years ago

7 0

Adiabatic process is that process in which heat of a closed system will remain conserved or we can say that system can not exchange its thermal energy from its surrounding

So here from 1st law of thermodynamics we can say

$\Delta Q = \Delta U + W$

since we know that

$\Delta Q = 0$

so we will have

$0 = \Delta U + W$

so we have

$-\Delta U = W$

so here correct answers are

A. -ΔU = W

B. Heat is constant.

You might be interested in

Absolute zero (K=0 or -273.15°C) is what temperature on the Farenheit scale? a) 459.4°F b) -301.43 °F c) 233.05°F d) -40.15°F e

ANEK [815]

Answer:

e) None of these is true

Explanation:

Given that

Temperature = 0 K

We know that relationship between kelvin and Farenheit scale

$\dfrac{K-273}{100}=\dfrac{F-32}{180}$

Now by putting the values

$\dfrac{K-273}{100}=\dfrac{F-32}{180}$

$\dfrac{0-273}{100}=\dfrac{F-32}{180}$

So F= - 459.67°F

So we can say that 0 K is equal to - 459.67°F.

So the our option e is correct.

3 0

4 years ago

What is the force of a 3kg ball that is accelerating at 4 m/s/s

Dafna11 [192]

12 newtons is your answer

8 0

3 years ago

Read 2 more answers

What is the net torque on the square plate, with sides 0.2 m, from each of the three forces? F1=18 N, F2=26 N, and F3=14 N. Use

marshall27 [118]

Answer:

The net torque on the square plate is 2.72 N-m.

Explanation:

Given that,

Side = 0.2 m

Force $F_{1}=18\ N$

Force $F_{2}=26\ N$

Force $F_{3}=14\ N$

We need to calculate the torque due to force F₁

Using formula of torque

$\tau_{1}=-F_{1}d_{1}$

$\tau_{1}=-F_{1}\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{1}=-18\times\dfrac{0.2}{2}$

$\tau_{1}=-1.8\ N-m$

We need to calculate the torque due to force F₂

Using formula of torque

$\tau_{2}=F_{2}d_{2}$

$\tau_{2}=F_{2}\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{2}=26\times\dfrac{0.2}{2}$

$\tau_{2}=2.6\ N-m$

We need to calculate the torque due to force F₃

Using formula of torque

$\tau_{3}=F_{3}d_{3}$

$\tau_{3}=(F_{3}\sin45+F_{3}\cos45)\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{3}=0.1(14\sin45+14\cos45)$

$\tau_{3}=1.92\ N-m$

We need to calculate the net torque on the square plate

$\tau=\tau_{1}+\tau_{2}+\tau_{3}$

$\tau=-1.8+2.6+1.92$

$\tau=2.72\ N-m$

Hence, The net torque on the square plate is 2.72 N-m.

3 0

3 years ago

1. What happened to the force of friction when you increased the weight on the cart?

Romashka-Z-Leto [24]

I think there would be an increase in force of friction

3 0

3 years ago

The binding of acetylcholine to its receptor at the neuromuscular junction causes the opening of a

Rufina [12.5K]

Answer: opening of the nicotinic acetylcholine receptor channels.

Explanation:

Neuromuscular junction is a special junction formed between a motor neurone and a muscle fibre. The junction is fortified with nerves and receptors that helps in the transmission of signals from the motor neurone to the muscle fibre in order to bring about the desired voluntary movements through muscular contraction.

Nicotinic acetylcholine receptor are activated through the binding of acetylcholine at the neuromuscular junction. This action leads to influx of sodium ions to accomplish endplate potential.

7 0

3 years ago