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MakcuM [25]
3 years ago
15

Which of the following is true of an adiabatic process?

Physics
2 answers:
Fiesta28 [93]3 years ago
8 0

The answers are A,B,and D. APEX

poizon [28]3 years ago
7 0

Adiabatic process is that process in which heat of a closed system will remain conserved or we can say that system can not exchange its thermal energy from its surrounding

So here from 1st law of thermodynamics we can say

\Delta Q = \Delta U + W

since we know that

\Delta Q = 0

so we will have

0 = \Delta U + W

so we have

-\Delta U = W

so here correct answers are

<em>A. -ΔU = W  </em>

<em>B. Heat is constant. </em>

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Define mixture, heterogeneous, homogeneous, solution, colloid, suspension, solvent, solute, saturation.( please don't answer the
oksano4ka [1.4K]

Answer:

1) a substance made by mixing other substances together.

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4 0
2 years ago
Read 2 more answers
Which is the best example of Newton's First Law of Motion? A small, lightweight ball and a large, heavy ball are dropped off the
Marizza181 [45]
I believe the best example of Newton's First Law of motion would be the example or illustration with the basketball player. An object will move in a straight line or a given direction at a constant speed unless or until another force acts upon the object, causing a change in speed and or direction.
4 0
3 years ago
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Bài 4: Một vật dao động điều hòa với phương trình x = 4cos(4πt - π/3) cm.
ra1l [238]

Answer:

g

Explanation:

6 0
2 years ago
A ball is kicked horizontally at 4.6 m/s off of a cliff 13.4 m high. How far from the cliff will it land.
Mekhanik [1.2K]
<h3>Answer:</h3>

7.53 m

<h3>Explanation:</h3>

<u>We are given:</u>

Initial Horizontal Velocity of the Ball = 4.6 m/s

Initial Vertical Velocity of the Ball = 0 m/s

Height from which ball is kicked = 13.4 m

<u>Time taken by the ball to reach the ground:</u>

The ball has an initial vertical velocity of 0 m/s

it also has a downward acceleration of 10 m/s² due to gravity

<u>Solving for the time taken:</u>

s = ut + 1/2(at²)                 [second equation of motion]

replacing the values

13.4 = (0)(t) + 1/2 (10)(t²)

13.4 = 5t²

t² = 13.4/5                  [dividing both sides by 5]

t² = 2.68

t = 1.637 seconds     [taking the square root of both sides]

<u>Horizontal distance covered by the ball:</u>

Since there are no horizontal opposing forces on the ball,

the ball will more horizontally at a velocity of 4.6 m/s until it hits the ground

We calculated that the ball will hit the ground in 1.637 seconds

<u>Distance covered:</u>

s = ut + 1/2 (at²)                            [seconds equation of motion]

s = ut                                            [since a = 0m/s² in the horizontal plane]

replacing the values

s = 4.6 * 1.637

s = 7.53 m

Hence, the ball landed 7.53 m from the cliff

5 0
3 years ago
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