To solve the problem it is necessary to apply the concepts related to Byle's Law and Avogadro's Law.
The ideal gas equation would help us find the final solution to the problem, defined by
Where,
T= Temperature of the gas
R = Universal as constant
n = number of moles
V = Volume
P = Pressure
For our case we have that the mass of Zn is 2.2g in moles would be
![[tex]Zn = \frac{2.2}{65}](https://tex.z-dn.net/?f=%5Btex%5DZn%20%3D%20%5Cfrac%7B2.2%7D%7B65%7D)
[/tex]
We know that 1 mole of hydrogen gas is proceed by 1 mole of zinc and the result is 
, then Hydrogen can produce the same quantity,
Applying the previous equation we have that
Therefore the volume of hydrogen gas is collected is 0.829L
Answer:
Explanation:
from the question we have the following:
distance between Sacramento and los angles = 400 miles
speed of car A = 60 mph
start time of car A = 11 am
speed of car B = 75 mph
start time of car B = 12 pm
distance of Fresno from Los Angeles = 150 miles
- To start off let's allow car A to travel for one hour (from 11 am to 12 pm), during which it would have covered a distance of 60 miles.
- Now the time would be 12 pm and the distance between the two cars would be 400 - 60 (distance traveled by car A within 11 am to 12 pm) = 340 miles
- From 12 pm to the time both cars will meet, the distance covered by car A + distance covered by car B would be equal to 340 miles. Therefore
- Distance covered by car A = speed x time(t) = 60 x t = 60t
- Distance covered by car B = speed x time(t) = 75 x t = 75t
- 60t + 75t = 340 miles
- 135t = 340
- t = 2.51 hours
- Recall that at their meeting point, the distance covered by car B = 75t = 75 x 2.62 = 188.89 miles
- Since Fresno is 150 miles from Los Angeles, car B which is 188.89 miles from Los Angeles at their meeting point would be 188.89 - 150 = 38.89 miles from Fresno
- 38.89 miles would also be the distance of car A from Fresno since that is their meeting point.
Answer:
i think the answer is 12 ohms
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Answer:
Electrification induction
Answer:
a = 1.72 m/s²
Explanation:
The given kinematic equation is the 2nd equation of motion. The equation is as follows:
xf = xi + (Vi)(t) + (1/2)(a)t²
where,
xf = the final position = 5000 m
xi = the initial position = 1000 m
Vi = the initial velocity = 15 m/s
t = the time taken = 60 s
a = acceleration = ?
Therefore,
5000 m = 1000 m + (15 m/s)(60 s) + (1/2)(a)(60 s)²
5000 m = 1000 m + 900 m + a(1800 s²)
5000 m = 1900 m + a(1800 s²)
5000 m - 1900 m = a(1800 s²)
a(1800 s²) = 3100 m
a = 3100 m/1800 s²
<u>a = 1.72 m/s²</u>
