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jok3333 [9.3K]
3 years ago
6

wo slightly out of tune instruments will create beats when the same note is played. This is a pattern of louder and softer sound

s. A piano tuner uses this method to tune a piano. When two waves overlap, they each act as if the other is not there. This interaction is kno
Physics
1 answer:
Lostsunrise [7]3 years ago
5 0

This interaction is known as <em>constructive interference</em>.  It's a result of linear superposition.

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im bored and lonely put those two together and youve got me. any guys wanna create a zo.om just for fun. im dyying of boredom.
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just guys

Explanation:

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3 years ago
In the picture of the atom above, what subatomic particle does the letter A represent?
ra1l [238]

Answer:

Electron

Explanation:

In the picture, the letter A is pointing to an electron.

4 0
3 years ago
A long, nonconducting cylinder (radius = 6.0 mm) has a nonuniform volume charge density given by αr2, where α = 6.2 mC/m5 and r
erastovalidia [21]

Answer: 2.80 N/C

Explanation: In order to calculate the electric firld inside the solid cylinder

non conductor we have to use the Gaussian law,

∫E.ds=Q inside/ε0

E*2πrL=ρ Volume of the Gaussian surface/ε0

E*2πrL= a*r^2 π* r^2* L/ε0

E=a*r^3/(2*ε0)

E=6.2 * (0.002)^3/ (2*8.85*10^-12)= 2.80 N/C

5 0
4 years ago
Calculate the force experienced by a positive test charge of 8.1 × 10-9 coulombs if the electric field strength is 9.4 × 107 new
Arte-miy333 [17]
The electric force exerted by an electric field of intensity E on a charge q is equal to the product between E and q, so:
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5 0
3 years ago
Read 2 more answers
A closed-end organ pipe is used to produce a mixture of sounds. The third and fifth harmonics in the mixture have frequencies of
nexus9112 [7]

Answer:

F_1=366.67Hz

Explanation:

From the question we are told that:

Frequency of 3rd harmonics F_3=1100

Frequency of 5th harmonics F_3=1833

Generally the equation for Wavelength at 3rd Harmonics is mathematically given by

 \lambda_3=\frac{4}{3}l

Therefore

 F_3=\frac{3v}{4l}

Generally the equation for Wavelength at 1st Harmonics is mathematically given by

 \lambda_1=\frac{4}{1}l

Therefore

 F_1=\frac{v}{4l}

Generally the equation for the frequency of the first harmonic is mathematically given by

 F_1=\frac{F_3}{3}

 F_1=\frac{1100}{3}

 F_1=366.67Hz

7 0
3 years ago
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