A bowling ball and a bag of potato chips are dropped at the same time from a tall tower on the moon. there is no air on the moon
2 answers:
Answer:
they both will hit the surface of moon at same time
Explanation:
When a bowling ball and potato chips are dropped at the same time on surface of moon
then during the motion above the surface of moon they both will have only force of gravity due to moon
so we have
now the we can say that the acceleration of object on this surface is given as
since this acceleration on both objects is independent of their mass
so we can say that they both will hit the surface of moon at same time
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Answer:
The inductance of the inductor is 35.8 mH
Explanation:
Given that,
Voltage = 120-V
Frequency = 1000 Hz
Capacitor
Current = 0.680 A
We need to calculate the inductance of the inductor
Using formula of current
Put the value of Z into the formula
Put the value into the formula
Hence, The inductance of the inductor is 35.8 mH
Jane's mechanical energy at any time is
where
is the potential energy, while 
is the kinetic energy.
Initially, Jane is on the ground, so the altitude is h=0 and the potential energy is zero: U=0. She's running with speed v, so she has kinetic energy only:
Then she grabs the vine, and when she reaches the maximum height h, her speed is zero: v=0, and so the kinetic energy becomes zero: K=0. So now her mechanical energy is just potential energy:
But E must be conserved, so the initial kinetic energy must be equal to the final potential energy:
from which we can find h, the maximum height Jane can reach:
where
Initially, Jane is on the ground, so the altitude is h=0 and the potential energy is zero: U=0. She's running with speed v, so she has kinetic energy only:
Then she grabs the vine, and when she reaches the maximum height h, her speed is zero: v=0, and so the kinetic energy becomes zero: K=0. So now her mechanical energy is just potential energy:
But E must be conserved, so the initial kinetic energy must be equal to the final potential energy:
from which we can find h, the maximum height Jane can reach: