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s344n2d4d5 [400]

4 years ago

8

Which metal would cause the greatest increase in the temperature of the water in the calorimeter: the one with the highest speci

fic heat, or the one with the lower specific heat?

1 answer:

masha68 [24]4 years ago

4 0

<h3><u>Answer;</u></h3>

the one with the highest specific heat

<h3><u>Explanation;</u></h3>

The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius.
The specific heat of water is 1 calorie/gram °C or 4.186 joule/gram °C which is higher than any other common substance.
<em><u>A metal with the highest specific heat will cause the greatest increase in temperature of water in a calorimeter because the metal would hold more heat, and then transfer the greater quantity of heat to the water.</u></em>

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3 years ago

You are performing an experiment that requires the highest possible energy density in the interior of a very long solenoid. Whic

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Answer:

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3 years ago

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4 0

3 years ago

In the steady state 1.2 ✕ 1018 electrons per second enter bulb 1. There are 6.3 ✕ 1028 mobile electrons per cubic meter in tungs

bekas [8.4K]

Answer:

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Explanation:

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We can find the drift velocity replacing,

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7 0

4 years ago

0.5-lbm of a saturated vapor is converted to asaturated liquid by being cooled in a weighted piston-cylinder device maintained a

klio [65]

Answer:

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Explanation:

Given the data in the question;

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$(\frac{dP}{dT} )_{sat } = \frac{h_{fg}}{Tv_{fg}}$

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where $h_{fg$ is the change in enthalpy of saturated vapor to saturated liquid ( 250 Btu

T is the temperature ( 15 + 460 )R

m is the mass of water ( 0.5 Ibm )

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we substitute

$(\frac{dP}{dT} )_{sat } =( \frac{250Btu\frac{778Ibf-ft}{Btu} }{0.5})$ / $( (15+460)\frac{1.5}{0.5})$

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Now,

$(\frac{dP}{dT} )_{sat } =$ $(\frac{P_2 - P_1}{T_2 - T_1})_{sat$

where P₁ is the initial pressure ( 50 psia )

P₂ is the final pressure ( 60 psia )

T₁ is the initial temperature ( 15 + 460 )R

T₂ is the final temperature = ?

we substitute;

$T_2$ $= ( 15 + 460 ) + \frac{(60-50)psia(\frac{144in^2}{ft^2}) }{272.98}$

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$T_2 =$ 480.275 R

Therefore, boiling point temperature of this substance when its pressure is 60 psia is 480.275 R

3 0

3 years ago