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s344n2d4d5 [400]
4 years ago
8

Which metal would cause the greatest increase in the temperature of the water in the calorimeter: the one with the highest speci

fic heat, or the one with the lower specific heat?
Physics
1 answer:
masha68 [24]4 years ago
4 0
<h3><u>Answer;</u></h3>

the one with the highest specific heat

<h3><u>Explanation;</u></h3>
  • The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius.
  • The specific heat of water is 1 calorie/gram °C or 4.186 joule/gram °C which is higher than any other common substance.
  • <em><u>A metal with the highest specific heat will cause the greatest increase in temperature of water in a calorimeter because the metal would hold more heat, and then transfer the greater quantity of heat to the water.</u></em>
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6kg of human blood at a temperature of 65degees celcius is mixed with 4kg of human blood ata temperature of 20 degrees celcius .
Gennadij [26K]

Answer:

T_f=47^{\circ}

Explanation: Two samples of blood that have different masses and temperatures and are mixed, we have to find the final temperature of the mixture. the final temperature can be found using the following formula:

T_f=\frac{(m_1\cdot T_1+m_2T_2)}{(m_1+m_2)}\Rightarrow(1)

(1) Formula basically tells us that the product of mass and temperature remains constant throughout, so the addition of two products of the two separate blood samples would be equal to the product of final temperature and the total mass of the mixture. Mathematically this means that:

\mleft(m_1+m_2\mright)T_f=(m_1\cdot T_1)+(m_2T_2)

Using (1) and plugging in the corresponding values, we get the answer as follows:

\begin{gathered} T_f=\frac{(m_1\cdot T_1+m_2T_2)}{(m_1+m_2)}\Rightarrow(1) \\ m_1=6\operatorname{kg} \\ m_2=4\operatorname{kg} \\ T_1=65^{\circ} \\ T_2=20^{\circ} \\ \therefore\rightarrow \\ T_f=\frac{(6kg\cdot65^{\circ}+4\operatorname{kg}\cdot20^{\circ})}{(6kg+4\operatorname{kg})}=\frac{(390+80)}{10}=\frac{470}{10}=47^{\circ} \\ \therefore\rightarrow \\ T_f=47^{\circ} \end{gathered}

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In this image of a pendulum, where is the lowest potential energy found?
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Think about the formula for potential energy. (Surely you remember it):

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-- The acceleration of gravity doesn't change.

-- The only thing that changes is the height of the mass on the end.

So the potential energy is lowest when its height is the lowest.

That's position <em>B </em>.

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