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torisob [31]
3 years ago
7

A steel pot has a bottom with a cross sectional area of .1m2 and has a thickness of 1cm. The pot is filled with boiling water an

d the bottom of the pot is held at 200 degrees Celsius. The thermal conductivity of steel is 14 J/s m Co. How much heat is being conducted through the pot in one minute?
Physics
1 answer:
jenyasd209 [6]3 years ago
3 0

Answer:

840000 J/min

Explanation:

Area = A = 0.1 m²

Bottom of pot temperature = 200 °C

Thermal conductivity = k = 14 J/sm°C

Thickness = L = 1 cm = 0.01 m

Temperature of boiling water = 100 °C

From the law of heat conduction

Q = kAΔT/L

⇒ Q = 14×0.1×(200-100)/0.01

⇒ Q = 14000 J/s

Converting to J/minute

Q = 14000×60 = 840000 J/min

∴ Heat being conducted through the pot is 840000 J/min

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The Lyman series comprises a set of spectral lines. All of these lines involve a hydrogen atom whose electron undergoes a change
mihalych1998 [28]

Answer:

a) 1.2*10^-7 m

b) 1.0*10^-7 m

c) 9.7*10^-8 m

d) ultraviolet region

Explanation:

To find the different wavelengths you use the following formula:

\frac{1}{\lambda}=R_H(1-\frac{1}{n^2})

RH: Rydberg constant = 1.097 x 10^7 m^−1.

(a) n=2

\frac{1}{\lambda}=(1.097*10^7m^{-1})(1-\frac{1}{(2)^2})=8227500m^{-1}\\\\\lambda=1.2*10^{-7}m

(b)

\frac{1}{\lambda}=(1.097*10^7m^{-1})(1-\frac{1}{(3)^2})=9751111,1m^{-1}\\\\\lambda=1.0*10^{-7}m

(c)

\frac{1}{\lambda}=(1.097*10^7m^{-1})(1-\frac{1}{(4)^2})=10284375m^{-1}\\\\\lambda=9.7*10^{-8}m

(d) The three lines belong to the ultraviolet region.

8 0
3 years ago
You decide you want to carry a boulder home from the beach it is 30 centimeter on each side. It is made of granite, which has a
HACTEHA [7]
Volume = 30*30*30 = 27000 cm^3
density = 2.8 g/cm^3

mass = 27000*2.8 = 75600g = 75.6 kg
7 0
3 years ago
A passenger jet flies from one airport to another 1293 miles away in 2.1hours . Find average speed
JulsSmile [24]

The average speed is 615.7 mph (275.2 m/s)

Explanation:

The average speed of an object gives a measure of how fast an object is moving over a certain time interval. It is a scalar quantity, and it is calculated as follows

v=\frac{d}{t}

where

v is the average speed

d is the distance covered

t is the time interval

For the jet in this problem, we have:

d = 1293 mi is the distance covered

t = 2.1 h is the time interval

Therefore, the average  speed is:

v=\frac{1293}{2.1}=615.7 mph

We can also convert into SI units (m/s), keeping in mind that:

1 mi = 1609 m\\1 h = 3600 s

And so

v=615.7 \frac{mi}{h}\cdot \frac{1609 m/mi}{3600 s/h}=275.2 m/s

Learn more about average speed:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

6 0
3 years ago
2. If a car is moving down a straight highway at a constant speed of 70 miles per hour, it has no net
Lelu [443]
That would be True I think
4 0
2 years ago
An object was released from rest at height of 1.65 m with respect to ground. Determine the time it takes the object to reach the
vivado [14]

Answer:

The time taken by the object to reach the ground is 0.58 seconds.

Explanation:

Given that,

An object was released from rest at height of 1.65 m with respect to ground. We need to find the time taken by the object to reach the ground. Initial speed of the object is 0 as it is at rest. It will move downward under the action of gravity such that, the distance covered by the object is given by :

d=ut+\dfrac{1}{2}gt^2

d=\dfrac{1}{2}gt^2

t=\sqrt{\dfrac{2d}{g}}

t=\sqrt{\dfrac{2\times 1.65}{9.8}}

t = 0.58 seconds

So, the time taken by the object to reach the ground is 0.58 seconds. Hence, this is the required solution.

8 0
3 years ago
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