Answer: 2.223
Explanation:
HClO4, also known as perchloric acid, is a very strong. This means we can assume that complete dissociation occurs.
This means that:
[H+] = [HClO4] = <span>0.00598
pH = -log[H+]
pH = -log[</span><span>0.00598] = 2.223
Note: The base of the log is 10 (conventionally we don't write the base if it is 10)</span>
Answer:
Final [B] = 1.665 M
Explanation:
3A + 4B → C + 2D
Average rection rate = 3[A]/Δt = 4[B]/Δt = [C]/Δt = 2[D]/Δt
0.05600 M/s = 4 [B]/ 2.50 s
[B] = 0.035 M (concentration of B consumed)
Final [B] = initial [B] - consumed [B]
Final [B] = 1.700 M - 0.035 M
Final [B] = 1.665 M
Answer:
14.125
Explanation:
If my calculations are right.
- there are 44.0 moles in co2
- +20.0
- which equals 64
- there are 78.125 moles in O2 so just subtract it by 64 which gives you
- 14.125
MOLE CALCULATION
divide the mass of the material by its molar mass. The molar mass of a substance is the mass in grams of one mole of that substance.
SrSO₄(s) ⇄ Sr²⁺(aq) + SO₄²⁻(aq)
Ksp=[Sr²⁺][SO₄²⁻]
[Sr²⁺]=[SO₄²⁻]
Ksp=[Sr²⁺]²
[Sr²⁺]=√Ksp
[Sr²⁺]=√3.2*10⁻⁷=5.66×10⁻⁴ mol/L
Here,
Heat gain by the first sample of water + Heat lost by the second sample of water is equal to zero (0).
Now, Mass of water sample one = 108 g (given)
Mass of water sample two = 66.9 g (given)
Temperature for water sample one = 
Let, temperature for water sample two =x
And, final temperature = 
Now,
where, 
= final temperature
= initial temperature
Substitute all the given values in above formula:
[tex x =84.81^{0}C [/tex]
