The power is 
Explanation:
First of all, we need to find the acceleration of the car, which is given by
where
v = 60 mph = 26.8 m/s is the final velocity
u = 0 is the initial velocity
t = 10.0 s is the time
Substituting,
Now we can find the mass of the car by using Newton's second law:
where
F = 5300 N is the force applied
m is the mass
is the acceleration
Solving for m,
Now we can use the work-energy theorem, which states that the work done is equal to the change in kinetic energy of the car, to find the work:
And substituting,
Finally, we can find the power output of the car:
where
W is the work
t = 10.0 s is the time elapsed
Substituting,
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The frequency of the other wave is 613 Hz or 607 Hz.
The difference between the frequencies of two waves is called the beat frequency.
Here, one wave has a frequency 610 Hz and the beat frequency is 3 beats per second.
Which has a higher frequency is not mentioned. Therefore, there are two possibilities.
Δf = | 610 - 613 | = 3
or
Δf = | 610 - 607 | = 3
Therefore, the frequency of the other wave is 613 Hz or 607 Hz.
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Answer: minimum theoretical value of T = 750k
Explanation:
Assuming the the cycle is reversible and is ideal then
Wnet/Qh = Nmin .... equa 1
Equation 1 can be rewritten as
(Th -TL)/ Th ...equation 2
Th= temp of hot reservoir
TL= temp of low reservoir= 300
Wnet = power generated=10kw
He = energy transfer=10kj per cycle
Qhe = power transfer = (100/60)*10Kj = 16.67kw
Sub into equat 1
Nmin = 10/16.67 = 0.6
Sub Nmin into equation 2
Th = -TL/(Nmin -1) = -300k/(0.6 - 1)
Th =750k
Answer:
M = 0.730*m
V = 0.663*v
Explanation:
Data Given:
Conservation of Momentum:
Energy Balance:
Substitute Eq 2 into Eq 1
Using Eq 1
Answer: is so be smart and study hard you can always do it no mater what happens
Explanation:is this what you want
