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nignag [31]
3 years ago
6

What are some of the main types of force? Explain.

Physics
2 answers:
Shalnov [3]3 years ago
5 0
Answer:
1. applied force
2. gravitational force
3. normal force
4. frictional force
5. air resistance force
6. tension force
7. spring force
8. electrical force
9. magnetic force
LiRa [457]3 years ago
4 0
Applied force is this answer
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The brightest star in the night sky in the northern hemisphere is Sirius. Its distance from Earth is estimated to be 8.7 light y
katen-ka-za [31]

Answer:5.11(10)^{13}miles

Explanation:

A light year is a unit of length and is defined as "the distance a photon would travel in vacuum during a Julian year at the speed of light at an infinite distance from any gravitational field or magnetic field. "

In other words: It is the distance that the light travels in a year.  

This unit is equivalent to 5.879(10)^{12}miles, which mathematically is expressed as:

1Ly=5.879(10)^{12}miles

Doing the conversion:

8,7Ly.\frac{5.879(10)^{12}miles}{1Ly}=5.11(10)^{13}miles  This is the distance from Earth to Sirius in miles.

4 0
3 years ago
An unlit match is held near (not touching) a Bunsen flame. The match doesn't get hot enough to light because
ohaa [14]
The answer is option D)
this is because the heat radiated by the flame is mostly absorbed by the air surrounding it, so the air becomes hot and its density decreases (because of expansion), therefore it goes up and it is replaced by cooler air. since all of the hot air flies up, non goes side ways to heat up the match stick, hence it remains cool and does not light up.

option A) also sounds correct, but it isn't. this is because the flame IS hot enough to burn the match stick, it's just that the match stick is positioned the wrong way
6 0
3 years ago
Steel is made of atoms of iron and carbon. Would iron
Nadusha1986 [10]

Still need the answer??

7 0
3 years ago
Read 2 more answers
What is the maximum value of the magnetic field at a<br> distance2.5m from a 100-W light bulb?
MA_775_DIABLO [31]

To solve this problem we will apply the concepts related to the intensity included as the power transferred per unit area, where the area is the perpendicular plane in the direction of energy propagation.

Since the propagation occurs in an area of spherical figure we will have to

I = \frac{P}{A}

I = \frac{P}{4\pi r^2}

Replacing with the given power of the Bulb of 100W and the radius of 2.5m we have that

I = \frac{100}{4\pi (2.5)^2}

I = 1.2738W/m^2

The relation between intensity I and E_{max}

I = \frac{E_max^2}{2\mu_0 c}

Here,

\mu_0 = Permeability constant

c = Speed of light

Rearranging for the Maximum Energy and substituting we have then,

E_{max}^2 = 2I\mu_0 c

E_{max}=\sqrt{2I\mu_0 c }

E_{max} = 2(1.2738)(4\pi*10^{-7})(3*10^8)

E_{max} = 30.982 V/m

Finally the maximum magnetic field is given as the change in the Energy per light speed, that is,

B_{max} = \frac{E_{max}}{c}

B_{max} = \frac{30.982 V /m}{3*10^8}

B_{max} = 1.03275 *10{-7} T

Therefore the maximum value of the magnetic field is B_{max} = 1.03275 *10{-7} T

3 0
3 years ago
How much electrical energy is used by a 400 W toaster that is operating for 5
andrew11 [14]

Answer:

The answer is C. 120,000 J.

Explanation:

8 0
2 years ago
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