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3 years ago

Which of the following electron configurations for neutral atoms is correct?

Chemistry

1 answer:

pochemuha3 years ago

4 0

Answer:

the correct answer is argon: 1s 2^2s 2^2p 6^3s 2^3p^6

Explanation:

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For her school Science Fair, Alyssa designs an experiment to learn more about erosion. Her experimental set up is shown below. W

shutvik [7]

Answer:

if I am going to answer I need the set up

Explanation:

please show the set up and I will answer the question

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2 years ago

Why have we not drilled or mined deeper into earth ??

alexdok [17]

Scientists have determined that the center of the earth is 6371 km below the surface. But how has this been determined? Many people might answer that question by saying scientists can drill into the Earth with machines. However, the drilling rigs that scientists use can only drill about 20 km in the Earth which is not very deep! In other words, we can only drill into upper part of the crust of the earth. Extremely high temperatures and pressures within the Earth make drilling into it very difficult

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2 years ago

What group is the element NITROGEN in? 1 Group 4 2 Group 5 3 Group 2 4 Group 8

Butoxors [25]

Answer:

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2 years ago

Read 2 more answers

The reaction of ethane gas (C2H6) with chlorine gas produces C2H5Cl as its main product (along with HCl). In addition, the react

Kazeer [188]

Answer:

The percent yield of chloro-ethane in the reaction is 82.98%.

Explanation:

$C_2H_6+Cl_2\rightarrow C_2H_5Cl+HCl$

Moles of ethane = $\frac{300.0 g}{30 g/mol}=10 mol$

Moles of chlorine gases = $\frac{650.0 g}{71 .0 g/mol}=9.1549 mol$

As we can see that 1 mol of ethane react with 1 mole of chlorine gas.the 10 moles will require 10 mole of chlorine gas, but only 9.1549 moles of chlorine gas is present.

This means that chlorine gas is in limiting amount and amount of formation of chloro-ethane will depend upon amount of chlorine gas.

According to reaction , 1 mol of chloro ethane gives 1 mol of chloro-ethane.

Then 9.1549 moles of chlorien gas will give:

$\frac{1}{1}\times 9.1549 mol=9.1549 mol$ of chloro-ethane

Mass of 9.1549 moles of chloro-ethane:

9.1549 mol × 64.5 g/mol = 590.4910 g

Theoretical yield of chloro-ethane: 590.4910 g

Given experimental yield of chloro-ethane: 490.0 g

$\% Yield=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$\%Yield (C_2H_5Cl)=\frac{490.0 g}{590.4910 g}\times 100=82.98\%$

The percent yield of chloro-ethane in the reaction is 82.98%.

6 0

3 years ago

How would the number 3475.32 in be expressed in scientific notation? *

Anarel [89]

Explanation:

i think 3x10^5

hope this helps if not sorry

5 0

2 years ago