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Mandarinka [93]
3 years ago
8

Write a symbolic notation of an isotope of an element having 8 protons 8 electrons and 10 neutrons

Chemistry
1 answer:
Bezzdna [24]3 years ago
7 0

Answer:

                       ¹⁸₈O

Explanation:

                     The symbolic notation of an isotope of an element is generally written as;

                                                  ᵃₙX

Where;

                 a  =  Mass Number

                 n  =  Atomic Number

                 X  =  Element Symbol;

Mass number is the sum of neutrons and protons present in the nucleus. It is given as,

Mass Number  =  No. of Protons  +  No. of Neutrons

As Given

                 Mass  Number  =  8 + 10

                 Mass  Number  =  a  =  18

Also,

Atomic Number is defined as the number of protons contained in the nucleus of an atom. Hence, in this case;

                 Number of Protons = Atomic Number = n = 8

Also, the element with atomic number 8 in periodic table is Oxygen. Hence;

                 X  =  O

Therefore, The symbolic notation for given element is ¹⁸₈O.

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Nitrogen gas reacts with hydrogen gas to produce ammonia. How many liters of hydrogen gas at 95kPa and 15∘C are required to prod
viktelen [127]

Answer:

222.30 L

Explanation:

We'll begin by calculating the number of mole in 100 g of ammonia (NH₃). This can be obtained as follow:

Mass of NH₃ = 100 g

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3

= 17 g/mol

Mole of NH₃ =?

Mole = mass /molar mass

Mole of NH₃ = 100 / 17

Mole of NH₃ = 5.88 moles

Next, we shall determine the number of mole of Hydrogen needed to produce 5.88 moles of NH₃. This can be obtained as follow:

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

3 moles of H₂ reacted to produce 2 moles NH₃.

Therefore, Xmol of H₂ is required to p 5.88 moles of NH₃ i.e

Xmol of H₂ = (3 × 5.88)/2

Xmol of H₂ = 8.82 moles

Finally, we shall determine the volume (in litre) of Hydrogen needed to produce 100 g (i.e 5.88 moles) of NH₃. This can be obtained as follow:

Pressure (P) = 95 KPa

Temperature (T) = 15 °C = 15 + 273 = 288 K

Number of mole of H₂ (n) = 8.82 moles

Gas constant (R) = 8.314 KPa.L/Kmol

Volume (V) =?

PV = nRT

95 × V = 8.82 × 8.314 × 288

95 × V = 21118.89024

Divide both side by 95

V = 21118.89024 / 95

V = 222.30 L

Thus the volume of Hydrogen needed for the reaction is 222.30 L

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Answer:

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Explanation:

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