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wel
3 years ago
8

Which acid-base buffer is most crucial to maintaining homeostasis within the human body?

Chemistry
2 answers:
Andrei [34K]3 years ago
4 0

Answer:

e 2020 a

Explanation:

Igoryamba3 years ago
3 0

it is a i believe: Bicarbonate and carbonic acid (A)

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Suppose that a catalyst lowers the activation barrier of a reaction from 125kJ/mol to 55kJ/mol125⁢kJ/mol to 55kJ/mol. By what fa
sineoko [7]

Answer:

The factor of increasing reaction rate is 1,85x10¹².

Explanation:

Using arrhenius formula:

k = A e^\frac{-E_{a}}{RT}

Where k is rate constant; A is frecuency factor; Eₐ is activation energy; R is gas constant (0,008134 kJ/molK); T is temperature 25°C = 298,15K

Thus, replacing for an activation energy of 125 kJ/mol assuming A as 1:

k = 1,25x10⁻²²

When activation energy is 55kJ/mol:

k = 2,31x10⁻¹⁰

Thus, the factor of increasing reaction rate is:

2,31x10⁻¹⁰/1,25x10⁻²² =<em> 1,85x10¹²</em>

<em></em>

I hope it helps!

8 0
3 years ago
1. What two types of cells contain chloroplasts?
Vikentia [17]

Answer:

plant cells and eukroyatic algae

5 0
3 years ago
___CH4 + ___O2 → ___CO2 + ___H2O
DaniilM [7]
CH4 + 2O2 =======> CO2 + 2H2O
5 0
3 years ago
Determine how many oxygeng atoms are in 5.00 g of sample of sodium dichromate, na2cr2o7
vlada-n [284]

The number of oxygen atoms is in 5.00 g of sample of sodium dichromate, Na₂Cr₂O₇ is 1.125 x 10²³ atoms.

<h3>What is sodium dichromate?</h3>

Sodium dichromate is an inorganic compound. It is sued in tanning and mental illness.

The molar mass of sodium = 23 gm

The molar mass of Cr = 51.99 gm

The molar mass of oxygen = 16 gm

Molar mass of Na₂Cr₂O₇ = 2(23) + 2(51.99) + 7(16) = 261.98 gm

Number of moles in 7 gm = mass / molar mass = 7 / 261.98 = 0.0267 moles

1 mole of  Na₂Cr₂O₇ contains 7 moles of oxygen, therefore:

The number of moles of oxygen in 0.0267 moles = 0.0267 x 7 = 0.1869 moles

Thus, the number of atoms = 0.1869 x 6.02 x 10^23 = 1.125 x 10²³ atoms.

To learn more about sodium dichromate, refer to the link:

brainly.com/question/1444529

#SPJ4

6 0
2 years ago
A patient gets 2.1 L of fluid over 19 hours through an IV. The drop factor is 20 gtt/mL.Calculate the drip rate in drops per min
Aleks [24]
<span>The rate of infusion is 2.1L/19h or 2100mL/19h (as 1L = 100 mL).
       
To convert 19 hours to minutes we multiply as follows:
   
19 hours = (19 hours) x (60 minutes/1 hour) = 1140 minutes
       
So the rate of infusion becomes:
   
2100mL /1140 min
       
In order to converted mL to drops (gtt) we multiply the rate of infusion with the drop factor to get the drip rate:
       
(2100mL/1140min) x (20 gtt/mL) = 36.8 gtt/min</span>
8 0
3 years ago
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