The question is incomplete. The complete question is :
A 100.0 mL flask is filled with 0.065 moles of A and allowed to react to form B according to the reaction below. The following experimental data are obtained for the amount of A as the reaction proceeds. What is the average rate of appearance of B in units of M/s between t = 10 min. and t = 30 min.? Assume that the volume of the flask is constant. A(g) → B(g)
Time 0.0 10.0 20.0 30.0 40.0
Moles of A 0.065 0.051 0.042 0.036 0.031
Solution :
Consider the following reaction as follows :

The experiment data is given as follows :
Time (min) : 0.0 10.0 20.0 30.0 40.0
Moles of A : 0.065 0.051 0.042 0.036 0.031
According to the rate of reaction concept, the rate can be expressed as a consumption of the reactant and formation of the product as follows :
Average rate : ![$= -\frac{d[A]}{dt} = \frac{d[B]}{dt} $](https://tex.z-dn.net/?f=%24%3D%20-%5Cfrac%7Bd%5BA%5D%7D%7Bdt%7D%20%3D%20%20%5Cfrac%7Bd%5BB%5D%7D%7Bdt%7D%20%24)
Now we have to calculate the average rate between 10.0 to 30.0 min w.r.t. A as follows :
Rate 


Therefore, the rate = 
The molecular formula tell us what elements the atoms are, and how many moles and atoms are attributed toward each element.
The molecular model tells us how the atoms/elements are bonded together.
Molecular formula : CH4
H
l
Molecular model: H -- C -- H
l
<span> H</span>
Answer:
Sharing or covalent bonding is taking place.
Explanation:
The valence electron will be shared by both the atoms so that means that the election will move around both of the atoms.
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Answer:
Iodine. The reaction between hot iron and iodine vapor produces gray iron(II) iodide, and is much less vigorous. This reaction, the equation for which is given below, is difficult to carry out because he product is always contaminated with iodine. Iodine is only capable of oxidizing iron to the +2 oxidation state.