4. What instrument is used to measure mass?

a person jogs eight complete laps around a 400-m track in a total time of 15.1 min .calculate the average speed, in m/s .

valentinak56 [21]

The average speed in m/s of a person that jogs eight complete laps around a 400m track in a total time of 15.1 min is 0.44m/s.

<h3>How to calculate average speed?</h3>

Average speed of a moving body can be calculated by dividing the distance moved by the time taken.

Average speed = Distance ÷ time

According to this question, a person jogs eight complete laps around a 400m track in a total time of 15.1 min. The average speed is calculated as follows:

15.1 minutes in seconds is as follows = 906 seconds

Average speed = 400m ÷ 906s

Average speed = 0.44m/s

Therefore, the average speed in m/s of a person that jogs eight complete laps around a 400m track in a total time of 15.1 min is 0.44m/s.

Learn more about average speed at: brainly.com/question/12322912

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6 0

1 year ago

A(n) _____ is a gap in the geologic record where some rock layers have been lost because of erosion.

Elenna [48]

I'm not sure, I think it's option A.

Let me know if I'm wrong!

4 0

4 years ago

The simple act of walking requires single leg

OlgaM077 [116]

you are so wise how do you do it?

4 0

3 years ago

Read 2 more answers

1. What is the wave speed of a wave that has a frequency of 100 Hz and a wavelength of 0.30 m?

aivan3 [116]

Answer:

1. v = 30 m/s

2. v = 5 m/s

3. f = 40 Hz

4. f = 400 Hz

5. f = 300 Hz

6. λ = 0.772 m

7. λ = 0.386 m

8. λ = 0.625 m

9. v = 100 m/s

10. v = 50 m/s

Explanation:

The relationship between frequency, wavelength, and speed of a wave is given by the following formula:

$v = f\lambda$

where,

v = speed of wave

f = frequency of wave

λ = wavelength

1.

f = 100 Hz

λ = 0.3 m

Therefore,

v = (100 Hz)(0.3 m)

v = 30 m/s

2.

f = 50 Hz

λ = 0.1 m

v = (50 Hz)(0.1 m)

v = 5 m/s

3.

v = 20 m/s

λ = 0.5 m

$f = \frac{v}{\lambda} = \frac{20\ m/s}{0.5\ m}$

f = 40 Hz

4.

v = 80 m/s

λ = 0.2 m

$f = \frac{v}{\lambda}=\frac{80\ m/s}{0.2\ m}$

f = 400 Hz

5.

v = 120 m/s

λ = 0.4 m

$f = \frac{v}{\lambda}=\frac{120\ m/s}{0.4\ m}$

f = 300 Hz

6.

v = 340 m/s

f = 440 Hz

$\lambda = \frac{v}{f}=\frac{340\ m/s}{440\ Hz}\\$

λ = 0.772 m

7.

v = 340 m/s

f = 880 Hz

$\lambda = \frac{v}{f}=\frac{340\ m/s}{880\ Hz}\\$

λ = 0.386 m

8.

v = 250 m/s

f = 400 Hz

$\lambda = \frac{v}{f}=\frac{250\ m/s}{400\ Hz}\\$

λ = 0.625 m

9.

f = 50 Hz

λ = 2 m

v = (50 Hz)(2 m)

v = 100 m/s

10.

f = 100 Hz

λ = 0.5 m

v = (100 Hz)(0.5 m)

v = 50 m/s

6 0

3 years ago

Two loudspeakers are placed on a wall 3.00 m apart. A listener stands 3.00 m from the wall directly in front of one of the speak

Mashutka [201]

Answer:

Part a)

$\Delta \phi = 2.2 \pi$

Part b)

$f = 411.3 Hz$

Explanation:

As we know that the observer is standing in front of one speaker

So here the path difference of the two sound waves reaching to the observer is given as

$\Delta x = 3\sqrt2 - 3$

$\Delta x = 1.24 m$

now phase difference is related with path difference as

$\Delta \phi = \frac{2\pi}{\lambda}(\Delta x)$

$\Delta \phi = \frac{2\pi}{\lambda}(1.24)$

here in order to find the wavelength

$\lambda = \frac{c}{f}$

$\lambda = \frac{340}{300} = 1.13$

now we have

$\Delta \phi = \frac{2\pi}{1.13}(1.24) = 2.2\pi$

Part b)

Now we know that when phase difference is odd multiple of $\pi$

then in that case the the sound must be minimum

So nearest value for minimum intensity would be

$\Delta \phi = 3\pi$

so we have

$3\pi = \frac{2\pi}{\lambda}(1.24)$

so we have

$\lambda = 0.827$

now we have

$\frac{340}{f} = 0.827$

$f = 411.3 Hz$

4 0

3 years ago

4. What instrument is used to measure mass?​

4. What instrument is used to measure mass?