Answer:
x=22.33m
Explanation:
Kinematics equation for constant deceleration:
EXERCISE 1
1 answer:
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Answer:
See the answers below
Explanation:
To solve this problem we must use the following equation of kinematics.
where:
Vf = final velocity [m/s]
Vo = initial velocity [m/s]
a = acceleration [m/s²]
t = time [s]
<u>First case</u>
Vf = 6 [m/s]
Vo = 2 [m/s]
t = 2 [s]
<u>Second case</u>
Vf = 25 [m/s]
Vo = 5 [m/s]
a = 2 [m/s²]
<u>Third case</u>
Vo =4 [m/s]
a = 10 [m/s²]
t = 2 [s]
<u>Fourth Case</u>
Vf = final velocity [m/s]
Vo = initial velocity [m/s]
a = acceleration [m/s²]
t = time [s]
<u>Fifth case</u>
Vf = final velocity [m/s]
Vo = initial velocity [m/s]
a = acceleration [m/s²]
t = time [s]
Answer:
W = 113.98 N
Explanation:
Given that,
Radius of Potatoine
Mass of Potatoine,
Mass of Marvin, m = 35 kg
We need to find his weight on Potatoine. Weight of an object is given by :
W = mg
g is acceleration due to gravity,
So,
So, his weight on Potatoine is 113.98 N.