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Natali5045456 [20]
3 years ago
15

A 1490-kg car is moving due east with an initial speed of 29.5 m/s. After 9.14 s the car has slowed down to 18.8 m/s. Find the m

agnitude of the net force that produces the deceleration.
Physics
1 answer:
zalisa [80]3 years ago
8 0

Answer:

The magnitude of the net force that produces the deceleration = 1744 N

Explanation:

Using the equations of motion, we can find the deceleration of the car and thereby find the magnitude of the met force that produces such deceleration

v = u + at

where v = final velocity = 18.8 m/s

u = initial velocity = 29.5 m/s

t = 9.14 s

a = ?

v = u + at

18.8 = 29.5 + 9.14a

9.14a = 18.8 - 29.5 = -10.7

a = - 1.171 m/s²

Magnitude of Force causing deceleration = ma = 1490 × 1.171 = 1744 N

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The ground state energy of an oscillating electron is 1.23 eV. How much energy must be added to the electron to move it to the t
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  • The energy that must be added to the electron to move it to the third excited state is  -1.153 eV
  • The energy that must be added to the electron to move it to the fourth excited state is  -1.181 eV

Explanation:

Given;

Energy of electron in ground state (n = 1 ) = 1.23 eV

E₁ = 1.23 eV

Eₙ = E₁ /n²

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E₁ is the energy of the electron in ground state

n is the energy level,

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E₄ = E₁ /4²

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The energy that must be added to the electron to move it to the third excited state is  -1.153 eV

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