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Leto [7]
3 years ago
15

Suppose that the Millennium Falcon orbits the Death Star 20,000m above the Star’s surface. Calculate the circular orbit velocity

in m/s

Physics
1 answer:
Nataly [62]3 years ago
5 0

Answer:

18.4 m/s

Explanation:

The gravitational force between the Death Star and the Millenium Falcon is equal to the centripetal force that keeps the Millenium Falcon in circular orbit:

G\frac{Mm}{(R+h)^2}=m\frac{v^2}{R+h}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

M=5.1\cdot 10^{17} kg is the mass of the planet

m=1.36\cdot 10^6 kg is the mass of the Millennium Falcon

v is the orbital velocity of the Millennium Falcon

R=\frac{160,000 m}{2}=80,000 m is the radius of the Death Star

h=20,000 m is the altitude of the Millennium Falcon above the planet's surface

Solving the equation for v, we find the orbital velocity:

v=\sqrt{\frac{GM}{R+h}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.1\cdot 10^{17} kg)}{80,000 m+20,000 m}}=18.4 m/s

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Answer:

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Explanation:

According to the problem, Q is the charge on the non conducting sphere of radius R. Let ρ be the volume charge density of the non conducting sphere.

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