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Alina [70]
3 years ago
6

Newton's Cradle.A Newton's cradle is composed of row metal balls, each hung from a string attached to a horizontal rod, so that

when they are rest, they are nearly touching each other (and form a neat line). Explain and prove (mathematically!) why, releasing balls causes the same number of balls on the other side of the cradle to be ejected?
Physics
1 answer:
denis-greek [22]3 years ago
4 0

Answer:

In Newton's Cradle there are N number of balls are suspended from the thread such that they all touch each other.

Now when we pull one ball apart and released then after the collision one ball on the other side moves up

Then in next time if we pull two balls from one side then after collision it will pull upwards exactly two balls on the other side after collision.

So here the number of balls on the other side is exactly same every time we pull the balls.

This is due to the conservation of momentum principle

As we know that all the balls are identical here then when we pull any number of balls on one side and then release them then after collision the momentum of the balls is transferred to same amount of the balls on the other side

Since there is no external force on this system so we can say that that this momentum conservation will exist for all cases and all number.

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They do the method 3 times to be sure. Because if you do it once, that could mean anything. If you do it twice, it may or may not have the same result. If you do it 3 times and it matches one of the previous answers, then it's likely that it's correct.
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Interdependence between plants and animals<br>​
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Answer:

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Explanation:

5 0
3 years ago
A 0.0450-kg golf ball initially at rest is given a speed of 25.2 m/s when a club strikes. part a part complete if the club and b
Ksenya-84 [330]
We are given information:
m = 0.0450 kg
Δv = 25.2 m/s
Δt = 1.95 ms = 0.00195s

To find force we use formula:
F = m * a

a is acceleration. To find it we use formula:
a = Δv / Δt 
a = 25.2 / 0.00195
a = 12923.1 m/s^2

Now we can find force:
F = 0.0450 * 12923.1
F = 581.5 N 


To check the effect of the ball's weight on this movement we need to calculate it and then compare it to this force.
W = m * g
W = 0.0450 * 9.81
W = 0.44145 N 

We can see that weight is much smaller than the applied force so it's influence in negligible.
3 0
3 years ago
A small charged bead has a mass of 1.9 g . it is held in a uniform electric field e⃗ = (200,000 n/c, up). when the bead is relea
dmitriy555 [2]

As we know that when charge is released in electric field

It will have two forces on it

1. electrostatic force

2. gravitational force

now if the ball will accelerate upwards so we can say

net upward force = mass * acceleration

qE - mg = ma

q*200000 - 1.9 * 10^{-3}* 9.8 = 1.9 * 10^{-3}* 15

now we can find charge q on it by above equation

q = 0.2356 * 10^{-6} C

So above is the charge on the particle

7 0
3 years ago
How would the weight of a 7-kilogram concrete block compared to the weight of a 7-kilogram metal sphere?
Hitman42 [59]

Answer:

C. The block and the sphere would have the same weight.

Explanation:

If both the block and the sphere weigh 7 kilograms then they have the same weight. They may look different, but they both weigh 7 kilograms.

3 0
3 years ago
Read 2 more answers
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