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4 years ago

Forces contribute to the net force on a car rolling down a ramp.

1 answer:

6 0

<span>B)Gravity pulls the car downward, also its the only force in the downward direction.
C)Force that acts against is friction. </span>

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Tarzan swings back and forth on a

WARRIOR [948]

Answer:

Considering Tarzan as a point mass at point L and using the equation for a simple pendulum:

P = 2 pi (L / g)1/2

P^2 = 4 pi^2 L / g

L = g P^2 / (4 pi^2) = 9.8 m/s^2 * 7.27^2 s^2 / (4 pi^2) = 13.1 m

4 0

3 years ago

A mass is oscillating horizontally on a spring. At the locations A, B, C, D, and E, photogates are used to measure the speed of

svetoff [14.1K]

Complete Question

The complete question is is shown on the first uploaded

Answer:

The elastic potential energy at point B is $PE_{elastic} = 50J$

The kinetic energy at point D is $KE = 75J$

Explanation:

Looking at the given point we can observe that mechanically energy(i.e potential and kinetic energy ) is conserved and it value is $E_ {m} = 100J$

So at point B

$E_{m} = PE_{elastic} +KE$

$100 = PE_{elastic} + KE$

KE at point B is 50J

So $PE_{elastic} = 100 - 50 = 50J$

Now at point D

$E_{m} = PE_{elastic} +KE$

$PE_{elastic}$ at point D is 25J

So $KE = 100 - 25 = 75J$

4 0

3 years ago

John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?

umka21 [38]

The horizontal component of the velocity is equal to: D. 15 m/s.

<u>Given the following data:</u>

Velocity = 30 m/s

Angle = 60°

To determine the horizontal component of the velocity:

The horizontal component of the velocity represents the influence of velocity in displacing an object or projectile in the horizontal direction.

Mathematically, the horizontal component of velocity is given by the formula:

$V_x = Vcos(\theta)$

Substituting the given parameters into the formula, we have;

$\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5$

Horizontal component, Vx = 15 m/s

Read more on horizontal component here: brainly.com/question/24681896

6 0

3 years ago

A radio wave has a frequency of 8.6 × 108 hz. what is the energy of one photon of this radiation (h = 6.63 × 10–34 j • s)?

My name is Ann [436]

Answer: $57.018\times10^{-26}J$

Energy is directly proportional to the frequency.

The energy of a photon is given by:

$E=h\nu$

Where, E is the energy and $\nu$ is the frequency.

Frequency of the radio wave is given:

$\nu=8.6\times10^8 Hz$

$h=6.63\times10^{-34}J.s$

Multiply the above two:

Energy,

$E=h\nu=6.63\times10^{-34}J.s\times8.6\times10^8 Hz= 57.018\times10^{-26}J$

Hence, the energy of each photon of radio wave having frequency $\nu=8.6\times10^8 Hz$ is $57.018\times10^{-26}J$

5 0

3 years ago

Technician A says that gaskets are used to fill a space or gap between two objects to prevent leakage from occurring. Technician

natta225 [31]

Answer:C

Explanation:the both are telling us more about a gasket

4 0

4 years ago