Which of the following is true of gases?

Chemistry

2 answers:

sleet_krkn [62]3 years ago

8 0

Answer:

B. Gases mix easily because of their high kinetic energy and low intermolecular forces

Explanation:

Gases have higher kinetic energy compared to solid and liquid because the large intermolecular spaces makes a large amount of movement between particles possible. The movements of the particles exhibits kinetic energy.

Gases are highly compressible because its particles aren’t tightly packed together. The intermolecular spaces are large and makes it easier for the gas particles to be compressed in a space which makes option A incorrect.

Gases have Low intermolecular molecules which explains why they aren’t tightly packed together which makes C incorrect.

Gases have a low density because the particles aren’t tightly packed together unlike the solids which are tightly packed together and denser than the liquid and gas which makes option D incorrect

r-ruslan [8.4K]3 years ago

3 0

Answer:

The answer to your question is A. Gases are not easily compressed because of expansion and limited space between particles.

You might be interested in

What factor would speed up a chemical reaction

vekshin1

Answer:

Adding Catalyst can Speed up a Chemical reaction

8 0

2 years ago

Read 2 more answers

(select all that apply.) the elements most often found in organic molecules are _____.

Arturiano [62]

C. Carbon. H. Hydrogen. N. Nitrogen. O. Oxygen. P. Phosphorus. S. Sulfur.

7 0

3 years ago

Read 2 more answers

How many grams are in 3 moles of Rf? O 785 0 784 0786 O 783

tensa zangetsu [6.8K]

The answer is 0784 the second one

5 0

3 years ago

Given the two reactions H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.57×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.46×10−19, what is the equilib

Dvinal [7]

Answer: The value of $K_c$ for the final reaction is $7.16\times 10^{25}$

Explanation:

The given chemical equations follows:

Equation 1: $H_2S(aq.)\rightleftharpoons HS^-(aq.)+H^(aq.);K_1$

Equation 2: $HS^-(aq.)\rightleftharpoons S^{2-}(aq.)+H^(aq.);K_2$

The net equation follows:

$S^{2-}(aq.)+2H^+(aq.)\rightleftharpoons H_2S(aq.);K_c$

As, the net reaction is the result of the addition of reverse of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of inverse of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

$K_c=\frac{1}{K_1}\times \frac{1}{K_2}$