Answer:
Explanation:
The I₂ is the common substance in the two equations.
(1) IO₃⁻ + 5I⁻ + 6H⁺ ⟶ 3I₂ + 3H₂O
{2) I₂ + 2S₂O₃²⁻ ⟶ 2I⁻ + S₄O₆²⁻
From Equation (1), the molar ratio of iodate to iodine is
From Equation (2), the molar ratio of iodine to thiosulfate is
Combining the two ratios, we get
Answer:
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Answer:
If
0.0357
mol
CaCl
2
is dissolved in water to make a
0.420
M
solution, what is the volume of the solution?
The temperatures of the gases will not be equal as oxygen gas will have a higher temperature than hydrogen gas because it has fewer moles overall.
<h3>Briefing :</h3>
The mechanical behavior of ideal gases is described by the ideal gas law. It has the ability to compute the volume of gases created or absorbed.
This equation is frequently used in chemical equations to convert between volumes and molar quantities.
According to the ideal gas law, there is a relationship between gas pressure, temperature, and volume.
PV = nRT
V is the same for both
So,
T is same for both.
When n increases, T decreases, so since n for hydrogen gas is 1 and n for oxygen gas is 0.5, it follows that oxygen gas will have a higher temperature than hydrogen gas because it has fewer moles overall.
To know more about ideal gases :
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moles NaOH = c · V = 0.2432 mmol/mL · 24.75 mL = 6.0192 mmol
moles H2SO4 = 6.0192 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.0096 mmol
Hence
[H2SO4]= n/V = 3.0096 mmol / 38.94 mL = 0.07729 M
The answer to this question is [H2SO4] = 0.07729 M
