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True [87]
4 years ago
9

.A system can have a nonzero velocity while the net external force on it is zero. Describe such a situation.

Physics
2 answers:
USPshnik [31]4 years ago
7 0

Answer:

Yes, a system can have a non-zero velocity.

Explanation:

When the net force is zero, applying Newton's second law, the net force is:

F = mass * acceleration

Acceleration can be defined as the change in velocity over time. Since the net force is zero, it also means that the acceleration is zero, since the speed is not changing, but the speed is not equal to zero. If a body moves with a constant velocity other than zero, this body has a net force equal to zero.

lakkis [162]4 years ago
6 0

Answer:

Explanation:

According to the Newton's second law of motion

F = m a

where, f be the force , m be the mass and a be the acceleration.

According to the question, F = 0

So, a = 0

a = v - u / t

So, v - u = 0

v = u

That means the velocity is constant.

If a body is moving with constant velocity, its acceleration is zero but velocity is non zero.

For example, a car is moving on a straight track with constant speed and in the same direction is the example in which velocity is non zero but acceleration is zero.

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3 years ago
3.A golf ball is hit of it’s tee, 200m down the fairway.
Alinara [238K]

<u>Answers:</u>


3. The diagrams showing the forces acting on the golf ball are in the figure attached. Let’s have a detailed look:


a) Here the ball is under 2 forces:


F1 which is called The Normal force and is perpendicular to the surface of the tee where the ball rests


-F1, related to the gravity force, to the weight of the ball, and has the same magnitude, but the opposite direction (That’s why it has a negative sign).



In this case the sum of the forces is 0



b) Here we have again forces F1 and –F1, but in this very moment the club strikes the ball and we have:


F2, the force of the strike





c) While the ball is in its flight, it is under the following forces:


F1, the force of the lift through the air


-F2, the gravity force

-F3, the force of air resistance, also called drag


F4, the tangencial force of the ball flight




4. Here are the sizes and directions of the resultant forces:


i)Two forces of the same magnitude or size are applied to this block, but in opposite directions (in the x-axis). This is expressed as:



F=-10N+10N=0 The resulting force is zero



ii) Two forces of different size and opposite directions in the y-axis are applied to this block. The sum of the forces is:



F=30N-40N=-10N This means the resulting force is 10N applied downwards



iii) In this case the only force applied to the block is -5N applied downwards



iv) Here there are four forces applied to the block.  

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F1=10N-10N=0 This means the applied force in the y-axis is zero



In the x-axis we have two forces of different size and opposite directions:



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4 0
3 years ago
If the gravitational field strength at the top of Mount Everest is 9.772 N/kg, approximately how tall (in feet) is
Delicious77 [7]

Answer:

The height of the Everest mountain is, x =  8514.087 m

Explanation:

Given data,

The gravitational field strength at the top of mount Everest, gₓ = 9.772 m/s²

The formula for gravitational field strength is,

                               <em> gₓ = GM/(R+x)²</em>

Where, x is the height from the surface of the Earth

Therefore,

                                (R+x)² = GM/gₓ

                                     x = √(GM/gₓ) - R

Substituting the values,

                       x = √(6.67408 x 10⁻¹¹ X  5.972 x 10²⁴ / 9.772) - 6.378 x 10⁶

                       x =  8514.087 m          

Therefore, the height of the Everest mountain is, x =  8514.087 m                                                              

6 0
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