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3 years ago

Which of the following are considered pure substances? element compound homogeneous mixture heterogeneous mixture

Chemistry

1 answer:

NeX [460]3 years ago

3 0

Answer:

element and compound.

Explanation:

reason

an element is a pure substance that cannot be broken down into simpler substances by any ordinary physical or chemical process.

and compound is a pure substance that consists of two or more elements held together in fixed proportions by natural forces called chemical bonds.

homogeneos and heterogenous mixtures are considered impure substances because they dont have a definite composition.

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Which gases are responsible for global warming?

elena-s [515]

Answer:

Greenhouse gas Chemical formula Global Warming Potential, 100-year time horizon

Carbon Dioxide

Methane

Nitrous Oxide

Chlorofluorocarbon

Explanation:

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3 years ago

Do oxygen atoms become more stable or less stable when oxygen forms compounds? Explain

4vir4ik [10]

They become more stable because they achieve a full outer shell of valence electrons with the magic number of 8.

5 0

3 years ago

Read 2 more answers

Match the following with their correct molecular weight. 2-butanone Propyl acetate 4-methyl-2-pentanone Butyl acetate Methanol E

Hatshy [7]

Answer:

2-butanone = 72.11 g/mol (option F)

Propyl acetate = 102.13 g/mol (option C)

4-methyl-2-pentanone = 100.16 g/mol (option D)

Butyl acetate = 116.16 g/mol (option B)

Methanol = 32.04 g/mol (option E)

Ethanol = 46.07 g/mol (option A)

Explanation:

Step 1: Data given

Molar mass of C = 12.01 g/mol

Molar mass of H = 1.01 g/mol

Molar mass of O = 16.00 g/mol

Step 2:

2-butanone = C4H8O

⇒ 4*12.01 + 8*1.01 + 16.00 = 72.11 g/mol (option F)

Propyl acetate = C5H10O2

⇒ 5*12.01 + 10*1.01 + 2*16.00 = 102.13 g/mol (option C)

4-methyl-2-pentanone = C6H12O

⇒ 6*12.01 + 12*1.01 + 16.00 = 100.16 g/mol (option D)

Butyl acetate = C6H12O2

⇒ 6*12.01 + 12*1.01 + 2*16.00 = 116.16 g/mol (option B)

Methanol = CH3OH = CH4O

⇒ 12.01 + 4*1.01 + 16.00 = 32.04 g/mol (option E)

Ethanol = C2H5OH = C2H6O

⇒ 2*12.01 + 6*1.01 + 16.00 = 46.07 g/mol (option A)

4 0

3 years ago

The compound sodium carbonate is a strong electrolyte. Write the reaction when solid sodium carbonate is put into water:

Ludmilka [50]

The compound sodium carbonate is a strong electrolyte because it completely dissociates when placed in water into its component ions. The equation of the reaction can be expressed as:

$Na_2CO_3_{(s)} ---> 2 Na^+_{(aq)} + CO_3^{(2+)}_{(aq)}$

The dissociation leads to the formation of sodium and carbonate ions with the latter held together by its internal covalent bond.

This is unlike weak electrolytes that do not dissociate completely in water or aqueous solutions. Only a small fraction of the solute exists as ions in the solution.

More on strong and weak electrolytes can be found here: brainly.com/question/3410548

7 0

3 years ago

What is the answer?

Solnce55 [7]

Answer: D

Explanation: because of because

5 0

4 years ago