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lidiya [134]
3 years ago
10

PLZZZ ANSWER FAST Describe each of the 4 different atomic models. Give the Scientist Name Name of model What they could account

for What they could not account for (flaws)
Chemistry
1 answer:
VladimirAG [237]3 years ago
5 0

Dalton's model of the atom (ESAAO) ...

Thomson's model of the atom (ESAAP) ...

Rutherford's model of the atom (ESAAQ) ...

Bohr's model of the atom (ESAAR) ...

IamSugarBee

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Which Of the following compounds is an electrolyte?
Anettt [7]
Hello,

Here is your answer:

The proper answer to this question is option D "<span>sodium hydroxide".

Here is how:

Sodium Hydroxide its a white substance that is a </span><span>electrolyte.

Your answer is D.

If you need anymore help feel free to ask me!

Hope this helps!</span>
8 0
3 years ago
What is the concentration of H+ in a 2.5 M HCl solution?
Pavel [41]

Answer:

The concentration of H⁺ in a 2.5 M HCl solution is 2.5 M

Explanation:

As HCl is a strong acid and hence a strong electrolyte, it will dissociate as

HCl ⟶ H⁺ + Cl⁻

So, The concentration of H⁺ will be 2.5 M (same as HCl)

Thus, The concentration of H⁺ in a 2.5 M HCl solution is 2.5 M

<u>-TheUnknownScientist</u><u> 72</u>

6 0
3 years ago
Read 2 more answers
What type of elements form metallic bonds?​
astra-53 [7]

Answer:

Aluminum , iron , gold , silver , nickels etc are the type of elements form metallic bonds .

8 0
3 years ago
Calculate the percent ionization of formic acid (hco2h) in a solution that is 0.311 m in formic acid and 0.189 m in sodium forma
ohaa [14]
<span>Answer: 0.094%


</span><span>Explanation:
</span>
<span></span><span /><span>
1) Equilibrium chemical equation:
</span><span />

<span>Only the ionization of the formic acid is the important part.
</span><span />

<span>HCOOH(aq) ⇄ HCOO⁻(aq) + H⁺(aq).
</span><span />

<span>2) Mass balance:
</span><span />

<span>                   HCOOH(aq)     HCOO⁻(aq)     H⁺(aq).

Start             0.311                 0.189

Reaction       - x                      +x                   +x

Final             0.311 - x          0.189 + x            x


3) Acid constant equation:
</span><span />

<span>Ka = [HCOO-] [N+] / [HCOOH] = (0.189 + x) x / (0.311 -x)
</span><span />

<span>= (0.189 + x )x / (0.311 - x) = 0.000177


4) Solve the equation:


You can solve it exactly (it will lead to a quadratic equation so you can use the quadratiic formula). I suggest to use the fact that x is much much smaller than 0.189 and 0.311.
</span><span />

<span>With that approximation the equation to solve becomes:


</span><span>0.1890x / 0.311 = 0.000177, which leads to:</span>
<span /><span>
x = 0.000177 x 0.311 / 0.189 = 2.91 x 10⁻⁴ M


5) With that number, the percent of ionization (alfa) is:
</span><span />

<span>percent of ionization = (moles ionized / initial moles) x 100 =
</span><span>
</span><span>
</span><span>percent ionization = (concentration of ions / initial concentration) x 100 =
</span><span>
</span><span>
</span><span>percent ionization = (0.000291 / 0.311)x 100 = 0.0936% = 0.094%
</span>
<span></span><span />
8 0
3 years ago
Which of the following breaks and forms bonds?
svp [43]
Your answer would be "Chemical Change"
7 0
3 years ago
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