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Lesechka [4]
4 years ago
12

Two objects, one with a mass of 2 kg and one with a mass of 3 kg are attracted to each other by a gravitational force. If the fo

rce on one mass is 4 N, what is the force on the other mass?
Physics
1 answer:
Tresset [83]4 years ago
8 0
By Newton's 3rd law: That for every action there is an equal and opposite reaction.

So if force on one mass is 4N, then the force on the other mass is -4N.
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If the speed of sound is approximately 671 mi/hr, about how many meters per second is it? (1mile=1609m)
zzz [600]
671mi/hr

= 671/60min (calculates miles/min)
= (671/60) ÷ 60seconds (calculates miles/sec)

((671/60) ÷ 60)× 1609m
= 299.899 meters/sec
= 299.90m (round off to 2 decimals )
3 0
4 years ago
An ideal spring is mounted horizontally, with its left end fixed. The force constant of the spring is 170 N/m. A glider of mass
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Answer:

A) The new amplitude = 0.048 m

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3 years ago
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Work output of a large machine in a factory is 89,000 joules, and it’s input is 102,000 joules. Work output of a similar machine
mojhsa [17]
(89000/102000)×100
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7 0
3 years ago
Read 2 more answers
Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour in 2.22 s starting from rest. Assuming that they have constan
elena55 [62]

Answer:

10.07m/s^2

Explanation:

Information we have:

velocities:

initial velocity: v_{i}=0mph (starts from rest)

final velocity: v_{f}=50mph

time:  t=2.22s

Since we need the answer in m/s^2, we nees to convert the speed to meters per second:

v_{f}=\frac{50miles}{1hour}(\frac{1hour}{3,600s} )(\frac{1609.34meters}{1mile} ) \\\\v_{f}=\frac{50*1609.34}{3600} m/s\\\\v_{f}=22.35m/s

We find the acceleration with the following formula:

a=\frac{v_{f}-v_{i}}{t}

substituting the known values:

a=\frac{22.35m/s-0m/s}{2.22s}\\ \\a=10.07m/s^2

the acceleration is 10.07m/s^2

8 0
3 years ago
Read 2 more answers
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