<span>The radio frequency characteristic that best determines the range of a 2.4 GHz ism signal is the wavelength.
This frequency can be used in WiFi and can reach up to 46 meters when indoors and about 92 meters when outdoors.
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Answer:
0.96 m
Explanation:
First, convert km/h to m/s.
162.3 km/h × (1000 m/km) × (1 hr / 3600 s) = 45.08 m/s
Now find the time it takes to move 20 m horizontally.
Δx = v₀ t + ½ at²
20 m = (45.08 m/s) t + ½ (0 m/s²) t²
t = 0.4436 s
Finally, find how far the ball falls in that time.
Δy = v₀ t + ½ at²
Δy = (0 m/s) (0.4436 s) + ½ (-9.8 m/s²) (0.4436 s)²
Δy = -0.96 m
The ball will have fallen 0.96 meters.
The Coulomb force between two or more charged bodies is the force between them due to Coulomb's law. If the particles are both positively or negatively charged, the force is repulsive; if they are of opposite charge, it is attractive. ... Like the gravitational force, the Coulomb force is an inverse square law.
Answer
given,
current (I) = 16 mA
circumference of the circular loop (S)= 1.90 m
Magnetic field (B)= 0.790 T
S = 2 π r
1.9 = 2 π r
r = 0.3024 m
a) magnetic moment of loop
M= I A
M=![16 \times 10^{-3} \times \pi \times r^2](https://tex.z-dn.net/?f=16%20%5Ctimes%2010%5E%7B-3%7D%20%5Ctimes%20%5Cpi%20%5Ctimes%20r%5E2)
M=![16 \times 10^{-3} \times \pi \times 0.3024^2](https://tex.z-dn.net/?f=16%20%5Ctimes%2010%5E%7B-3%7D%20%5Ctimes%20%5Cpi%20%5Ctimes%200.3024%5E2)
M=![4.59 \times 10^{-3}\ A m^2](https://tex.z-dn.net/?f=4.59%20%5Ctimes%2010%5E%7B-3%7D%5C%20A%20m%5E2)
b) torque exerted in the loop
![\tau = M\ B](https://tex.z-dn.net/?f=%5Ctau%20%3D%20M%5C%20B)
![\tau = 4.59 \times 10^{-3}\times 0.79](https://tex.z-dn.net/?f=%5Ctau%20%3D%204.59%20%5Ctimes%2010%5E%7B-3%7D%5Ctimes%200.79)
![\tau = 3.63 \times 10^{-3} N.m](https://tex.z-dn.net/?f=%5Ctau%20%3D%203.63%20%5Ctimes%2010%5E%7B-3%7D%20N.m)
First let us calculate for the angle of inclination using
the sin function,
sin θ = 1 m / 4 m
θ = 14.48°
Then we calculate the work done by the movers using the
formula:
W = Fnet * d
So we must calculate for the value of Fnet first. Fnet is
force due to weight minus the frictional force.
Fnet = m g sinθ – μ m g cosθ
Fnet = 1,500 sin14.48 – 0.2 * 1,500 * cos14.48
Fnet = 84.526 N
So the work exerted is equal to:
W = 84.526 N * 4 m
<span>W = 338.10 J</span>