Change in velocity of larger moose: (1/3)v - v = -(2/3)v

<span>change in velocity of small moose: (1/3)v - (-v) = (4/3)v </span>

<span>- (change in velocity of larger moose)/(change in velocity of smaller moose) = 2

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First, let's take a look at the equation for the force of gravity between two objects:

F = (GMm)/r², where,

G = gravitational constant = 6.67 x 10⁻¹¹

M = mass of one object

m = mass of the other object

r = distance between the two objects

From this equation, we can see that the force of gravity is directly proportional to the mass of the two objects and inversely proportional to the distance between them. We can then say that the Earth is <span>more attracted to the sun than the moon because of the massive mass of the Sun (1.9891 x 10</span>³⁰)<span> compared to moon (7.3577 x 10</span>²²<span>). Although, the moon is nearer to the Earth, it has little effect to bring down the gravitational pull of the Sun. </span>

**Answer:**

0.256 hours

**Explanation:**

<u>Vectors in the plane
</u>

We know Office A is walking at 5 mph directly south. Let be its distance. In t hours he has walked

Office B is walking at 6 mph directly west. In t hours his distance is

Since both directions are 90 degrees apart, the distance between them is the hypotenuse of a triangle which sides are the distances of each office

This distance is known to be 2 miles, so

t is approximately 15 minutes

Answer:1.008 ×10^-14/rJ

Where r is the distance from.which the charge was moved through.

Explanation:

From coloumbs law

Work done =KQq/r

Where K=9×10^9

Q=7×10^-6C

q=e=1.6×10^-19C

Micro is 10^-6

W=9×10^9×7×10^-6×1.6×10^-19/r=100.8×10^-16/r=1.008×10^-14/rJ

r represent the distance through which the force was used to moved the charge through.