Answer:
endoplasmic reticulum:
✔ helps in the production and movement of materials
Golgi body:
✔ packages and distributes materials in and out of cell
mitochondrion:
✔ supplies energy that the cell uses
ribosome:
✔ produces proteins for the cell
Explanation:
took test :D
Let the total mass of compound is 100g
The mass of each element will be
Al = 22.10 g
P = 25.40 g
O = 52.50 g
In order to determine the molecular formula we will calculate the molar ratio of the given elements
Atomic weight of Al : 27 g/ mol
Atomic weight of P : 3 1g /mol
Atomic weight of O : 16 g /mol
Moles of Al = mass / atomic mass = 22.10 / 27 = 0.819
Moles of P = mass / atomic mass = 25.40/ 31 = 0.819
Moles of O = mass / atomic mass = 52.50/ 16 = 3.28
Now we will divide the moles of each element with the lowest moles obtained to obtain a whole number ratio of moles of each element present
moles of Al = 0.819 / 0.819 = 1
moles of P = 0.819 / 0.819 = 1
moles of O = 3.28 / 0.819 = 4
So the empirical formula will be : AlPO4
Answer: B
Explanation:
I think this is false. I really don't know the explination, but due to me just finishing this class. I'm going to go with B.
Answer:
Explanation:
The<em> heat</em> to <em>vaporize</em> a l<em>iquid</em> is equal to the amount of liquid in moles multiplied by the specific <em>heat of vaporiztion</em> per mole.
First, calculate the number of moles in 35.5g of <em>butane</em>.
- Molar mass of butane: 58.124 g/mol
- Number of moles = mass in grams/molar mass
- Number of moles = 35.5g / 58.124g/mol = 0.6107632mol
Now, calculate the heat to vaporize that amount of <em>liquid butane</em>:
- Heat = number of moles × specific heat of vaporization
- Heat = 0.6107632mol × 21.3kJ/mol = 13.0 kJ
The answer must be reported with 3 significant figures.
