Answer:
2m/s²
Explanation:
When an object starts or at its state of rest it has an Initial speed U = 0
Final speed = 6m/s
total time taken for the acceleration = 3s
Acceleration =?
Acceleration is the change in velocity (speed) with time
OR
Time rate of change of velocity
Acceleration = <u>Change in Speed(velocity)</u>
Time taken
Hence,
Acceleration = <u> </u><u> </u><u>V - </u><u>U</u><u> </u><u> </u>
t
a = <u>6</u><u> </u><u>-</u><u> </u><u>0</u>
3
a = <u>6</u><u> </u><u> </u>
3
a = 2m/s²
Answer:
As the temperature of a fixed volume of a gas increase the pressure will increase.
Explanation:
According to the Gay- Lussac's Law,
" The pressure of given amount of gas is directly proportional to the temperature at a constant volume"
Mathematical expression:
P ∝ T
P = CT
P / T = C
As the temperature increase, the pressure also increase.
The initial and final expression of volume and pressure can be written as,
P₁ / T₁ = P₂ / T₂
Answer:
The volume that the sample of oxygen would occupy at 25 ° C if the pressure were reduced to 760.0 torr is 40.2 L
Explanation:
Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant, so that the pressure of a gas in a closed container is inversely proportional to the volume of the container. That is, if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.
Boyle's law is expressed mathematically as:
Pressure * Volume = constant
or P * V = k
Considering an initial state 1 and a final state 2, it is true:
P1* V1= P2*V2
In this case:
- P1= 20.1 L
- V1= 1520 torr
- P2= 760 torr
- V2= ?
Replacing:
20.1 L* 1520 torr= 760 torr* V2
Solving:

V2= 40.2 L
<em><u>The volume that the sample of oxygen would occupy at 25 ° C if the pressure were reduced to 760.0 torr is 40.2 L</u></em>
<em><u></u></em>
Answer:
<h3>An acid that contains more than one ionizable proton is a polyprotic acid. The protons of these acids ionize in steps. The differences in the acid ionization constants for the successive ionizations of the protons in a polyprotic acid usually vary by roughly five orders of magnitude.</h3>