Answer:
0.96kg/s
Explanation:
Hello! To solve this exercise we must use the first law of thermodynamics, which states that the sum of the energies that enter a system is the same amount that must go out. We must consider the following!
state 1 : is the first flow in the input of the chamber
h1=entalpy=335.02KJ/kg
m1=mass flow=0.56kg/s
state 2 : is the second flow in the input of the chamber
h2=entalpy=83.915KJ/kg
state 3:is the flow that comes out
h3=entalpy=175.90 kJ/kg
now use the continuity equation that states that the mass flow that enters is the same as the one that comes out
m1+m2=m3
now we use the first law of thermodynamics
m1h1+m2h2=m3h3
335.02m1+83.915m2=175.9m3
as the objective is to find the cold water mass flow(m2) we divide this equation by 175.9
1.9m1+0.477m2=m3
now we subtract the equations found in the equation of continuity and first law of thermodynamics
m1 + m2 = m3
-
1.9m1 + 0.477m2=m3
----------------------------------
-0.9m1+0.523m2=0
solving for m2
the mass flow rate of the cold-water is 0.96kg/s
Answer:
I = 0.625 A
Explanation:
Given that,
Power of the light bulb, P = 75 W
Voltage of the circuit, V = 120 V
We need to find the current flowing through it. We know that, Power is given by :
I is the electric current
So, the current is 0.625 A.
Answer:
heater wattage = 4.32 kW
Explanation:
given data
volume flow rate of air = 0.1 m³/s
temperature t1 = 15°C
temperature t2 = 50°C
relative humidity RH = 80%
pressure = 101.325 kPa
to find out
heater wattage
solution
we will get here h value from psychometric chart with the help of temperature
that is
h1 = 37 kJ/kg
and
h2 = 73 kJ/kg
and v1 = 0.829 m³/kg
so here heater wattage formula is
heater wattage = m ( h2 -h1) ......1
here m is
m = V/v1 = 0.1 / 0.819 = 0.12 kg/s
so from equation 1
heater wattage = 0.12 ( 75 -39 )
heater wattage = 4.32 kW
-i3R3 - e2 = 0 loop law of kirchhoff voltage law
<u>Explanation:</u>
As we know that the parallel conductors carrying current in opposite directions repel each other , therefore induced current in right loop is counterclockwise so as to experience a force towards right ( repelling force) as shown in the figure that has been attached
All the other options are not in the parameter in loop and junction law. loop law of kirchh off voltage law and All the other operations are not valid under kirch off the voltage law.