What is matter that is composed of more than one substance

A satellite in the shape of a solid sphere of mass 1,900 kg and radius 4.6 m is spinning about an axis through its center of mas

konstantin123 [22]

Answer:

Therefore, the new rotation rate of the satellite is 6.3 rev/s.

Explanation:

The expression for conservation of the angular momentum (L) is

$L_{i} = L_{f} I_{i}\times\omega_{i} = I_{f}\times\omega_{f}$

Where

$I_{i}\ and \ \omega_{i}$ initial moment of inertia and angular velocity

$I_{f}\ and \ \omega_{f}$ is the final moment of inertia and angular velocity

The expression of moment of inertia of the satellite (a solid sphere) is

$I_{i} = \frac{2}{5}m_{s}r^{2}$

Where $m_{s}$ is the satellite mass

r is the radus of the sphere

Substititute 1900kg for m and 4.6m for r

$I_{i} = \frac{2}{5}m_{s}r^{2}\\\\ = \frac{2}{5}\times1900 kg\times (4.6 m)^{2} \\\\= 1.61 \cdot 10^{4} kgm^{2}$

The final moment of inertia of the satellite about the centre of mass

$I_{f} = I_{i} + 2\timesI_{x} \\\\= 1.61 \cdot 10^{4} kgm^{2} + 2\times\frac{1}{3}m_{x}l^{2}$

Where $m_{x}$ is the antenna's mass and

I is the length of the antenna

$I_{f} = 1.61 \cdot 10^{4} kgm^{2} + 2\times\frac{1}{3}150.0 kg\times(6.6 m)^{2} \\\\= 2.05 \cdot 10^{4} kgm^{2}$

So, the Final rotation rate of the satellite is:

$I_{i}\times\omega_{i} = I_{f}\times\omega_{f} \\\\\omega_{f} = \frac{I_{i}\times\omega_{i}}{I_{f}} \\\\= \frac{1.61 \cdot 10^{4} kgm^{2}\times8.0 \frac{rev}{s}}{2.05 \cdot 10^{4} kgm^{2}} \\\\= 6.3 rev/s$

Therefore, the new rotation rate of the satellite is 6.3 rev/s.

5 0

4 years ago

A laser beam of wavelength λ=632.8 nm shines at normal incidence on the reflective side of a compact disc. The tracks of tiny pi

anzhelika [568]

Answer:

The intensity of light be maximum is for angles 23.3° and 52.3°.

Explanation:

Given that,

Wave length = 632.8 nm

Distance = 1.60 μm

We need to calculate the intensity of light be maximum

Using Bragg's law

$d\sin\theta=n\lambda$

$\theta=\sin^{-1}(\dfrac{n\lambda}{d})$

We need to calculate the angle for different value of n

Using Bragg's law

$\theta=\sin^{-1}(\dfrac{n\lambda}{d})$

For n₁,

Put the value into the formula

$\theta=\sin^{-1}(\dfrac{632.8\times10^{-9}}{1.60\times10^{-6}})$

$\theta=23.3^{\circ}$

For n₂,

$\theta=\sin^{-1}(\dfrac{2\times632.8\times10^{-9}}{1.60\times10^{-6}})$

$\theta=52.3^{\circ}$

Hence, The intensity of light be maximum is for angles 23.3° and 52.3°.

6 0

3 years ago

Which of the following best represents a chemical reaction?

Sonja [21]

Answer:

The answer to your question should be D.

Explanation:

reactants are on the laft side of arrow and products are on right side of arrow

7 0

3 years ago

A transverse wave has a frequency of 200 Hz with a wavelength of 1.0 m. Determine the speed

Lana71 [14]

Answer:

200 m\ s Ans .....

Explanation:

Data:

f = 200 Hz

w = 1.0 m

v = ?

Formula:

v = f w

Solution:

v = ( 200)(1.0)

v = 200 m\s Ans .........

7 0

3 years ago

Which of the following can only be dual sports? A. Paddleball B. Table tennis C. Racquetball D. Beach volleyball

stiks02 [169]

Answer:

I think beach volleyball is a dual sport.

7 0

3 years ago