In a solution, when the concentrations of a weak acid and its conjugate base are equal, the -log of the concentration of H+ and the -log of the Ka are equal.
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What is Henderson-Hasselbalch equation ?</h3>
- This formula is frequently used to determine the pH of buffer solutions. A weak acid and its conjugate base make up buffer solutions.
- To find the pH of the buffer solution, we obtain the pKa of the weak acid and add it to the log of the concentration of the conjugate base divided by the concentration of weak acid.
- So whenever the concentration of the weak acid is equal to the concentration of the conjugate base, the pH of the buffer solution is equal to the pKa of the weak acid.
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Answer:
C. 64
Explanation:
Given:
The number of equally likely sample outcomes of a single stage = 4
Unknown:
Total number of elements if there are three stages= ?
Solution;
Probability is the likelihood of an event to occur.
In this problem;
For a single stage, the likely outcome is 4
So therefore;
For the 3 stages 4 x 4 x 4 = 64
Therefore, the total number of elements in the sample space of an experiment with 3 stages is 64
Answer:
D. MgO
Explanation:
We need to look at the charge of element. (Look at a periodic table for this)
Mg, which is Magnesium, has a charge of 2+ because it's in the second column, or group, from the left.
O, which is Oxygen, has a charge of 2- because it's in the second column, or group, from the right.
Since Mg is 2+, it's the cation and since O is 2-, it's the anion. We can put these two elements together into an ionic compound.
Mg^(2+) and O^(2-) becomes Mg2O2, where we can cancel the 2s: MgO.
Thus, the answer is D.
Hope this helps!
For this problem, we use the Beer Lambert's Law. Its usual equation is:
A = ∈LC
where
A is the absorbance
∈ is the molar absorptivity
L is the path length
C is the concentration of the sample solution
As you notice, we only have to find the absorbance. But since we are not given with the molar absorptivity, we will have to use the modified equation that relates % transmittance to absorbance:
A = 2 - log(%T)
A = 2 - log(27.3)
A = 0.5638
