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densk [106]
3 years ago
8

The position vector of a particle of mass 1.70 kg as a function of time is given by r with arrow = (6.00 î + 5.70 t ĵ), where r

with arrow is in meters and t is in seconds. Determine the angular momentum of the particle about the origin as a function of time.
Physics
1 answer:
ollegr [7]3 years ago
7 0

Answer:

The angular momentum of the particle is 58.14 kg m²/s along positive z- axis and is independent of time .

Explanation:

Given that,

Mass = 1.70 kg

Position vector r=(6.00\hat{i}+5.70 t \hat{j})

We need to calculate the angular velocity

The velocity is the rate of change of the position of the particle.

v = \dfrac{dr}{dt}

v=\dfrac{d}{dt}(6.00\hat{i}+5.70 t \hat{j})

v=5.70\hat{j}

We need to calculate the angular momentum of the particle

Using formula of angular momentum

L=r\cdot p

Where, p = mv

Put the value of p into the formula

L=m(r\times v)

Substitute the value into the formula

L=1.70(6.00\hat{i}+5.70 t \hat{j}\times5.70\hat{j})

L=1.70\times34.2

L=58.14\ kgm^2/s

Hence, The angular momentum of the particle is 58.14 kg m²/s along positive z- axis and is independent of time .

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The approximate volume of table tennis ball is  80 cm³

<h3>What is volume?</h3>

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To find the volume of tennis ball using graduated cylinder.

Step 1 - Fill the graduated cylinder half or full.

Step 2 - Mark the initial volume of the water i.e. 100 cm³ (Vi)

Step 3  - Put the tennis ball in the graduated cylinder. Some of the water was displaced by the table tennis ball.

Step 4 - Mark the Final volume of the water (Vf) i.e. 180 cm³

Step 5 = Calculate the volume by using Formula

Vb = Vf – Vi = 180 cm³ - 100 cm³ = 80 cm³

Hence the volume of tennis ball (Vb) is 80 cm³

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Answer:

80Ω

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3 years ago
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Answer:

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Answer: A.

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What is the average de Broglie wavelength of oxygen molecules in air at a temperature of 27°C? Use the results of the kinetic th
asambeis [7]

Answer:

\lambda = 2.57 \times 10^{-11} m

Explanation:

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now we have

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\lambda = \frac{6.6 \times 10^{-34}}{(5.31\times 10^{-26})(483.4)}

\lambda = 2.57 \times 10^{-11} m

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