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barxatty [35]
2 years ago
10

The level of mercury falls in a barometerwhile taking it to a mountain.​

Physics
1 answer:
Alexxandr [17]2 years ago
8 0

Answer:

This is due to a relative decrease in atmospheric pressure in high places.

Explanation:

Given that atmospheric pressure decreases at the higher point or ground, this reduced atmospheric pressure, however, will be unable to contain the Mercury in the barometer tube.

Therefore, at the top of the mountain where the air pressure is low, the barometer reading ultimately goes down.

Hence, the level of mercury falls in a barometer while taking it to a mountain "due to a relative decrease in atmospheric pressure in high places."

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3 years ago
The urethra extends from the:
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2 years ago
At what temperature will silver have a resistivity that is two times the resistivity of iron at room temperature? (Assume room t
emmasim [6.3K]

Answer:

The temperature of silver at this given resistivity is 2971.1 ⁰C

Explanation:

The resistivity of silver is calculated as follows;

R_t = R_o[1 + \alpha(T-T_o)]\\\\

where;

Rt is the resistivity of silver at the given temperature

Ro is the resistivity of silver at room temperature

α is the temperature coefficient of resistance

To is the room temperature

T is the temperature at which the resistivity of silver will be two times the resistivity of iron at room temperature

R_t = R_o[1 + \alpha(T-T_o)]\\\\\R_t = 1.59*10^{-8}[1 + 0.0038(T-20)]

Resistivity of iron at room temperature = 9.71 x 10⁻⁸ ohm.m

When silver's resistivity becomes 2 times the resistivity of iron, we will have the following equations;

R_t,_{silver} = 2R_o,_{iron}\\\\1.59*10^{-8}[1 + 0.0038(T-20)] =(2 *9.71*10^{-8})\\\\\ \ (divide \ through \ by \ 1.59*10^{-8})\\\\1 + 0.0038(T-20) = 12.214\\\\1 + 0.0038T - 0.076 = 12.214\\\\0.0038T +0.924 = 12.214\\\\0.0038T  = 12.214 - 0.924\\\\0.0038T = 11.29\\\\T = \frac{11.29}{0.0038} \\\\T = 2971.1 \ ^0C

Therefore, the temperature of silver at this given resistivity is 2971.1 ⁰C

8 0
3 years ago
A rocket moves through outer space at 11,000 m/s. At this rate, how much time would be required to travel the distance from Eart
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11 km/s over 380,000km

380,000 / 11 = 34545.4 seconds

34545.4 / 60 = 575.7 minutes
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3 years ago
What conditions are typcial of the soil the deeper we dig into it?
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When we first dig into soil, it's nice and soft.( Depending on what soil it is; usually topsoil) 

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