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lozanna [386]
3 years ago
15

Using Charles’s law, V1/T1 =V2/T2 and the information below, solve the question. If a balloon takes up 625L at 273K, what will t

he new volume be when the balloon is heated to 353K.
Chemistry
1 answer:
pogonyaev3 years ago
4 0

Answer:

The new volume is 808L.

Explanation:

First, you need to set up your proportion, using Charles's law.

V1         V2

<u>      </u>  =   <u>      </u>

T1         T2

Then, substitute for the ones you already know.

625 L            V2

<u>           </u>   =    <u>           </u>

273 K          353 K

Then, you need to cross multiply.

625 x 353 = 273 x V2

Then, solve for V2.

220625 = 273 x V2

220625 ÷ 273 = V2

808 = V2

The final volume is 808L.

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Answer:

The pressure of the balloon is 0.98 atm

Explanation:

Using the equation P1V1 = P2V2, you can solve for the value of V2, which is 0.98 atm.

(P1V1)/P2 = V2

Plug in the numbers:

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What is the volume (ML) of water
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Answer:

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Using the electronegativity values in the chart below, which bond is the most polar?
lorasvet [3.4K]

Answer:

C-O

Explanation:

you have to check the all four bonds and find out their electronegativity difference. Whichever has the largest difference, is your answer.

  1. N-O = 3.04 - 3.44 = -0.4
  2. Cl-Cl = 3.16 -3.16 = 0
  3. C-O = 3.44 -  2.55 = 0.89
  4. C-H = 2.55 - 2.20= 0.35

Now check the differences, the largest electronegativity differences means the most polar bond

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3 years ago
Engine size is measured by how much air the cylinders displace. A 1996 Pontiac V8 has an engine size of 316.6 cubic inches. What
inna [77]

The size of this engine in cubic meters is 0.0052 m^{3}.

<u>Explanation:</u>

As it is stated that engine size can be measured depending upon the amount of air the cylinders displace, it is also stated that the engine of model Pontiac V8 has a size of 316.6 cubic inches. The problem is to convert the size of engine in cubic meters. We know that 1 inch = 0.0254 m.

Then 1 inch^{3}=(0.0254)^{3} m^{3}

As here the size of engine is 316.6 cubic inches, then in metres it will be

    316.6 \text { inches }^{3}=316.6 \times(0.0254)^{3} \mathrm{m}^{3}=0.0052 \mathrm{m}^{3}

Thus, the size of the engine in cubic meters will be 0.0052 m^{3}.

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4 years ago
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