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lozanna [386]
3 years ago
15

Using Charles’s law, V1/T1 =V2/T2 and the information below, solve the question. If a balloon takes up 625L at 273K, what will t

he new volume be when the balloon is heated to 353K.
Chemistry
1 answer:
pogonyaev3 years ago
4 0

Answer:

The new volume is 808L.

Explanation:

First, you need to set up your proportion, using Charles's law.

V1         V2

<u>      </u>  =   <u>      </u>

T1         T2

Then, substitute for the ones you already know.

625 L            V2

<u>           </u>   =    <u>           </u>

273 K          353 K

Then, you need to cross multiply.

625 x 353 = 273 x V2

Then, solve for V2.

220625 = 273 x V2

220625 ÷ 273 = V2

808 = V2

The final volume is 808L.

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Answer :

The concentration of H^+ before any titrant added to our starting material is 0.200 M.

The pH based on this H^+ ion concentration is 0.698

Explanation :

First we have to calculate the concentration of H^+ before any titrant is added to our starting material.

As we are given:

Concentration of HBr = 0.200 M

As we know that the HBr is a strong acid that dissociates complete to give hydrogen ion H^+ and bromide ion Br^-.

As, 1 M of HBr dissociates to give 1 M of H^+

So, 0.200 M of HBr dissociates to give 0.200 M of H^+

Thus, the concentration of H^+ before any titrant added to our starting material is 0.200 M.

Now we have to calculate the pH based on this H^+ ion concentration.

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pH=-\log [H^+]

pH=-\log (0.200)

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Learn more at: brainly.com/question/24089206?referrer=searchResults

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