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love history [14]
3 years ago
10

A solution is made by dissolving 3.35 g of fructose in 35.0 ml of water. What is the molality of fructose in the solution? Assum

e density of water is 1.00 g/ml.
Chemistry
1 answer:
ludmilkaskok [199]3 years ago
6 0

Answer:

m = 0.531 molal

Explanation:

∴ m fructose = 3.35 g

∴ V water = 35.0 mL

∴ ρ H2O = 1 g/mL

  • molality = moles solute / Kg solvent

∴ Mw fructose = 180.16 g/mol

⇒ moles fructose = 3.35 g * ( mol / 180.16 g) = 0.0186 mol fructose

⇒ m H2O = 35.0 mL * ( 1 g/mL ) * ( Kg/1000g) = 0.035 Kg H2O

⇒ molality (m) = 0.0186 mol fructose / 0.035 Kg H2O

⇒ m = 0.531 molal

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3 0
2 years ago
How many atoms of the element with atomic number 11 are in the reactants of the given formula?
liq [111]

The number of Na atoms in the reactants = 2

<h3>Further explanation</h3>

Every chemical reaction involves compounds that can act as reactants or products

The reactants will react to produce products

The reactants are usually written on the left side of the reaction, while the products on the right side of the reaction

Reaction

2 NaCl + H₂SO₄ → 2 HCl + Na₂SO₄

The element with atomic number 11  = Na(Natrium)

The number of atoms of the element that reacts or is produced can be seen from the reaction coefficient and the number of atoms in the compound

Na in NaCl = 1 atom

From equation, cofficient for NaCl = 2, so number of atoms of Na=2 x 1 = 2

3 0
3 years ago
find the volume of an item using a scale and waterA crown made of alloy of gold and silver has a volume of 60cm3and mass of 1050
KiRa [710]

Answer:

The mass of gold in crown is 960.61 g.And  the volume of gold is 49.77 cm^3.

Explanation:

Density is defined as mass of the substance present in unit volume of the substance.

Mass of gold in an alloy of crown= m

Mass of silver in an alloy of crown = M

Volume  gold in an alloy of crown= v

Volume of silver in an alloy of crown = V

Density of gold = 19.3 g/cm^3

Density of silver = 10.5 g/cm^3

Volume of the crown = 60 cm^3

60 cm^3=v+V

60 cm^3=\frac{m}{19.3 g/cm^3}+\frac{M}{10.5 g/cm^3}..(1)

Mass of eh crown = 1050 g

1050g =m+M..(2)

Solving equation (1) and (2):

m = 960.61 g

M = 89.39 g

Volume of the gold = v = \frac{960.61 g}{19.3 g/cm^3}=49.77 cm^3

Volume of silver = V = 60 cm^3-v=60 cm63-49.77 cm63=10.23 cm^3

The mass of gold in crown is 960.61 g.And  the volume of gold is 49.77 cm^3.

4 0
3 years ago
Given: logK=nE∘0.0592 What is the value K for this redox reaction? Zn2+(aq) + 2 Cl−(aq) → Zn(s) + Cl2(
anygoal [31]

<em>K</em> = 2.4 × 10^(-72)

<em>Step 1</em>. Determine the <em>value of n </em>

Zn^(2+) + 2e^(-) → Zn

2Cl^(-) → Cl_2 + 2e^(-)

Zn^(2+) + 2Cl^(-) → Zn + Cl_2

∴ <em>n</em> = 2

<em>Step 2</em>. Calculate <em>K</em>

log<em>K</em> = <em>nE</em>°/0.0592 V = [2 × (-2.12 V)]/0.0592 V = -71.62

<em>K</em> = 10^(-71.62) = 2.4 × 10^(-72)

8 0
3 years ago
Which best describes the result of tropical continental climate in the summer A.hot and sunny B.cool and cloudy
marysya [2.9K]
A. Hot and sunny would be the answer.Hope this helps :)

6 0
3 years ago
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