<span>Let's make a few assumptions.
1. The paratrooper's lowest speed will be just prior to impact.
2. Since the jump was from a relatively low altitude, the paratrooper used a static line and the parachute should have opened almost immediately upon jumping.
So let's convert 100 mi/h to ft/s
100 mi/h * 5280 ft/mi / 3600 s/h = 146.67 ft/sec
Given the 1st assumption above, the MAXIMUM distance the paratrooper would have fallen would be 8 seconds at 146.67 ft/s, so
8 s * 146.67 ft/s = 1173.36 ft
The calculated distance is close to the jump distance, which agrees with both assumptions 1 and 2. So this account does seem reasonable.
Additionally, looking for the speed of a parachutist doing a freefall in the belly-to-earth position with arms and legs outspread, they will generally reach a terminal velocity of 120 mi/h which is slightly faster than the 100 mi/h in the article. This too is in agreement with the defective parachute flapping and causing some extra air resistance.</span>
A dragster gets to a speed of 112 m/s over a distance of 300 m from the rest, then the acceleration will be 20.9 m/s².
<h3>What is Acceleration?</h3>
The rate of change in an object's velocity with respect to time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.
Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.
According to the question, the given values are :
Final velocity, v = 112 m/s.
Initial velocity, u = 0 m/s
Distance, s = 300 m.
Use the equation of motion,
v² - u² = 2as
112 ² - 0 = 2 (a)(300)
a = 12544/600
a = 20.9 m/s².
Hence, the acceleration of the dragster will be 20.9 m/s².
To get more information about Acceleration :
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Answer:
momentum of iron ball is greater than wooden ball
Explanation:
when metal ball (iron ball) and wooden drop are drop from same elevation and reaching the ground after same time. at this position the iron ball has greater momentum than wooden ball
we know that momentum is defined as
P=Mv
and we know also that mass of iron ball is greater than mass of wooden ball and they reached on ground at same time and same distance it mean also velocity will be same for both ball. therefore from above relation we have
Miron*V > Mwood*V i.e.
momentum of iron ball is greater than wooden ball
Acceleration = force / mass = 20 / 2 = 10 m/s^2
