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4 years ago

How does the mass-energy equation e = mc2 relate to fission

2 answers:

3 0

It relates because the energy of an object to its mass and since fission requires energy to do so, e=mc^2 relates to it.

solniwko [45]4 years ago

3 0

in a fission reaction a large nucleus gets broken in to smaller nuclei

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A car achieves a velocity 50 meters per second after 5 seconds. What is the Car's acceleration?

Reptile [31]

Answer: 10 m/s

Explanation: Velocity/Time

50/5= 10

7 0

3 years ago

Which liquid will evaporate the fastest water salt water pepsi and gatorade?

MArishka [77]

The liquid that will evaporate the quickest would be water.
~The rest are mixtures, and have more ingrediants in them, therefore the answer should be water. (in which it has no other ingrediants in it but water itself)

6 0

3 years ago

A 1.3-kg model airplane flies in a circular path on the end of a 23-m line. The plane makes

storchak [24]

(a) The plane makes 4.3 revolutions per minute, so it makes a single revolution in

(1 min) / (4.3 rev) ≈ 0.2326 min ≈ 13.95 s ≈ 14 s

(b) The plane completes 1 revolution in about 14 s, so that in this time it travels a distance equal to the circumference of the path:

(2π (23 m)) / (14 s) ≈ 10.3568 m/s ≈ 10 m/s

(c) The plane accelerates toward the center of the path with magnitude

a = (10 m/s)² / (23 m) ≈ 4.6636 m/s² ≈ 4.7 m/s²

(d) By Newton's second law, the tension in the line is

F = (1.3 kg) (4.7 m/s²) ≈ 6.0627 N ≈ 6.1 N

4 0

3 years ago

How much force is needed to accelerate a bicycle and rider with a total mass of 50 kg at a rate of 2.0 m/s2 ?

True [87]

Answer:

The answer is D 100 newton

Explanation:

2.0m/s2 is d acceleration while the 50kg is the mass. Force = mass x acceleration. So f=50x2.so force is 100 newton

8 0

3 years ago

Two satellites are orbiting earth at different altitudes. Which satellite orbits at a higher speed v around earth? Assume that t

alexandr1967 [171]

Answer:

a) the one with a lower orbit b) the one with a higher orbit

Explanation:

Let's consider orbital mechanics. To get an object in orbit, we need it to fall to earth parallel to the earth's surface. To understand it easily imagine a projectile thrown horizontally further and further away, at one point, the projectile hits the cannon from behind. Considering there is no wind resistance, that would be a projecile in orbit.

In other words, the circular orbits of some objects around a massive body are due to the equality between centrifugal acceleration and gravity acceleration.

$\frac{v^2}{r} = \frac{GM}{r^2}$ .

so the velocity is

$v = \sqrt{\frac{GM}{r} }$

where "G" is the gravitational constant, "M" the mass of the massive body and "r" the distance between the object and the center of gravity of mass M. As you can note, if "r" increase, "v" decrease.

The orbital period of any object in orbit is

$T = 2\pi \sqrt{\frac{a^3}{GM} }$

where "a" is length of semi-major axis (a = r in circular orbits). So if "r" increase, "T" increase.

3 0

4 years ago