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Stels [109]
3 years ago
5

A corn ethanol production plant receives 500,000.0 kg/day corn feedstock at a moisture content of 15.5% (wet basis). If all of t

his corn is converted into ethanol what is the theoretical volume of ethanol that this facility can produce per day? Assume that the starch content of corn grain is 68.5%. The density of ethanol is 789 kg/m3.
Engineering
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer:

207 m³/day

Explanation:

Dry corn feed stock = 500000 × ( 100 - 15.5%) = 500000 × 84.5% = 500000× 0.845 = 422500

Starch yield = 68.5% × 422500 = 289412.5

Glucose yield = 1.11 × 289412.5 = 321247.875 where 1.11 is the scarification factor of starch to glucose

Ethanol yield = 0.51 × 321247.875 = 163836.416 where 0.51 is theoretical yield of ethanol from one mole of glucose

density = mass / volume

volume = mass / density = 163836.416 / 789 = 207 m³ / day

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2 years ago
A fuel gas containing 45.00 mole% methane and the balance ethane is burned completely with pure oxygen at 25.00 degree C, and th
Dennis_Churaev [7]

Answer:

A)

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B )

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- Q ( KJ ) for liquid = - 1146.3 KJ

Explanation:

Given data :

45.00 % mole of methane

55.00 % of ethane

attached below is a detailed solution

A) calculate - Q(kw)

- Q ( kw ) for vapor =  -1258.05 kw

- Q ( kw ) for liquid = -1146.3 kw

B ) calculate  - Q ( KJ )

- Q ( kj ) for vapor  = -1258.05 kJ

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OleMash [197]

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