A corn ethanol production plant receives 500,000.0 kg/day corn feedstock at a moisture content of 15.5% (wet basis). If all of t his corn is converted into ethanol what is the theoretical volume of ethanol that this facility can produce per day? Assume that the starch content of corn grain is 68.5%. The density of ethanol is 789 kg/m3.
1 answer:
Answer:
207 m³/day
Explanation:
Dry corn feed stock = 500000 × ( 100 - 15.5%) = 500000 × 84.5% = 500000× 0.845 = 422500
Starch yield = 68.5% × 422500 = 289412.5
Glucose yield = 1.11 × 289412.5 = 321247.875 where 1.11 is the scarification factor of starch to glucose
Ethanol yield = 0.51 × 321247.875 = 163836.416 where 0.51 is theoretical yield of ethanol from one mole of glucose
density = mass / volume
volume = mass / density = 163836.416 / 789 = 207 m³ / day
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