Part 1)
here we know that supply took 10 s to reach the ground
so here we will have
Part 2)
Here all the supply covered horizontal distance of 650 m in 10 s interval of time
so here we can say
A certain lightbulb has a tungsten filament with a resistance of 20.3 Ω when at 20.0°C and 135 Ω when hot. Assume the resistivit
1 answer:
Answer:
1275.61° C
Explanation:
The resistance of a conductor varies as a function of temperature and it is given as follows
R_0 is the resistance at temperature T_0, R is the resistance at T and α is the coefficient of temperature of resistance
α= 0.0045/°C
R_0 = 20.3Ω T_0 = 20°C and R= 135Ω
T= 1275.61° C
Therefore the temperature of the hot filament = 1275.61° C
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Answer:
f1 = 12.90 Hz
Explanation:
To calculate the first harmonic frequency you use the following formula for n = 1:
( 1 )
It is necessary that the unist are in meters, then you have:
L: length of the string = 60cm = 0.6m
M: mass of the string = 0.05kg
T: tension on the string = 20 N
you replace the values of L, M and T in the expression (1) for getting f1:
Hence, the first harmonic has a frequency of 12.90 Hz