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3 years ago

Exploring the Second Law

Chemistry

1 answer:

san4es73 [151]3 years ago

5 0

Answer:

(a) The coefficient of performance of an irreversible refrigeration cycle is always less than the coefficient of performance of a reversible refrigeration cycle when both exchange energy by heat transfer with the same two reservoirs.

Explanation:

According to the Kelvin–Planck statement of the second law of thermodynamics ,it is not possible to construct a device which operates in cycle and does not produce effect on the environment than the production of work.

We know that

Coefficient of performance is the ratio of desired effect to the work input in a cycle.

Given all option is correct but most appropriate option is a.

So the option a is correct

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The amount of energy needed to heat 6.2 g of a substance from 50.0°C to 80.0°C is 27.4 J. What is the specific heat capacity of

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Answer:

The heat capacity for the sample is 0.913 J/°C

Explanation:

This is the formula for heat capacity that help us to solve this:

Q / (Final T° - Initial T°) = c . m

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san4es73 [151]

Answer : The change in internal energy is, 900 Joules.

Solution : Given,

Heat given to the system = +1400 J

Work done by the system = -500 J

Change in internal energy is equal to the sum of heat energy and work done.

Formula used :

$\Delta U=q+w$

where,

$\Delta U$ = change in internal energy

q = heat energy

w = work done

As per question, heat is added to the system that means, q is positive and work done by the system that means, w is negative.

Now put all the given values in the above formula, we get

$\Delta U=(+1400J)+(-500J)=900J$

Therefore, the change in internal energy is 900 J.

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