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babunello [35]
3 years ago
5

Exploring the Second Law

Chemistry
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

(a) The coefficient of performance of an irreversible refrigeration cycle is always less than the coefficient of performance of a reversible refrigeration cycle when both exchange energy by heat transfer with the same two reservoirs.

Explanation:

According to the  Kelvin–Planck statement of the second law of thermodynamics ,it is not possible to construct a device which operates in cycle and does not produce effect on the environment than the production of work.

We know that

Coefficient of performance is the ratio of desired effect to the work input in a cycle.

Given all option is correct but most appropriate option is a.

So the option a is correct

(a) The coefficient of performance of an irreversible refrigeration cycle is always less than the coefficient of performance of a reversible refrigeration cycle when both exchange energy by heat transfer with the same two reservoirs.

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Defination of dative covalent bond
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<h2>♨ANSWER♥</h2>

In coordination chemistry,

A coordinate covalent bond also known as a <em>dative bond, dipolar bond, or coordinate bond</em> is a kind of two-center, two-electron covalent bond in which the two electrons derive from the same atom. The bonding of metal ions to ligands involves this kind of interaction.

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5 0
2 years ago
Read 2 more answers
What is the mass of 6.78x1050 molecules of NaCl
ryzh [129]

Answer:

Explanation:

As

Molar mass of NaCl= 58.44 gm

So we got it that,

58.44 mass of NaCl contain = 6.023*10^23  molecules of Na Cl

x mass will contain = 6.78*10^50

by cross multiplication , we get

x=  58.44*(6.78*10^50)/  6.023*10^23  

x= 65.785 * 10^27  molecules

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6 0
3 years ago
Consider the following intermediate chemical equations.
QveST [7]

Answer: 250 kJ

Explanation: According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

P_4(s)+6Cl_2\rightarrow 4PCl_3  \Delta H_1=-2439kJ (1)

4PCl_5(g)\rightarrow P_4(s)+10Cl_2(g)  \Delta H_2=3438kJ (2)

Net chemical equation:

PCl_5(g)\rightarrow PCl_3(g)+Cl_2(g)  \Delta H=? (3)

Adding 1 and 2 we get,

4PCl_5(g)\rightarrow 4PCl_3(g)+4Cl_2 \Delta H_3=\Delta H_1+\Delta H_2=-2439+3438=1000kJ   (4)

Now dividing equation (4) by 4, we get

PCl_5(g)\rightarrow PCl_3(g)+Cl_2

\Delta H=\frac{\Delta H_3}{4}=\frac{1000kJ}{4}=250kJ   (4)

8 0
3 years ago
60 POINTS! PLEASE ANSWER!
Mumz [18]
I would have helped but I didn’t understand it sorry that I didn’t answer :(
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2 years ago
How will you prepare carbon dioxide gas on industrial scale? explain with chemical equation​
r-ruslan [8.4K]

Answer:

Explanation:

https://www.bbc.co.uk/bitesize/guides/zxgkp39/revision/3

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2 years ago
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