Answer:
a) The speed of the block immediately after the collision is .
b) The impulse exerted on the block is .
Explanation:
Hi
a) As this is a perfectly elastic collision, we can use the formula , due , we obtain . Then with the data that we know and , therefore or adding uncertainty.
b) Now that we know the speed we can use
Answer:
A) q = -8.488 cm
, B) m = 0.29
Explanation:
A) For this exercise in geometric optics, we will use the equation of the constructor
where p and q are the distance to the object and image, respectively and f is the focal length
in our case the distance the object is p = 29 cm the focal length of a diverging lens is negative and indicates that it is f = - 12 cm
we calculate
= - 0.1178
q = -8.488 cm
the negative sign indicates that the image is virtual
B) the magnification is given
we substitute
m =
m = 0.29
the positive sign indicates that the image is right
Answer:
12.45kgm/s
Explanation:
1.27kg x 9.8m/s = 12.446kgm/s
The sum of decimal point is 3 and the unit kg multiplies m divided by s
Answer:
0.04225 Nm
Explanation:
N = Force applied = 5 N
= Coefficient of static friction = 0.65
d = Diameter of knob = 1.3 cm
r = Radius of knob =
Force is given by
When we multiply force and radius we get torque
Torque on thumb
Torque on forefinger
The total torque is given by
The most torque that exerted on the knob is 0.04225 Nm