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Korolek [52]
2 years ago
6

How much does 100g grams of platinum cost

Physics
1 answer:
Bumek [7]2 years ago
7 0
Today (April 28), platinum closed at $1,012 per troy ounce,
and gold closed at $1,243 the ounce.

1 troy ounce = 31.1 grams.

So 100g of platinum would be worth  (100/31.1) x $1,012  =  $3,254

and 100g of gold would be worth  (100/31.1) x $1,243  =  $$3,997 (rounded). 

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A loop of current-carrying wire has a magnetic dipole moment of 5. 0 10–4 am2. if the dipole moment makes an angle of 57° with a
Digiron [165]

The potential energy will be 1.46*10^-4J.

To find the answer, we have to know about the torque acting on a current loop in a uniform magnetic field.

<h3>How to find the potential energy of the loop?</h3>
  • We have the expression for torque acting on a current loop in a uniform magnetic field as,

                         \tau=MBsin\theta

where; M is the magnetic dipole moment, B is the magnetic field , and theta is the angle between M and B.

  • As we know that, the torque is equal to force times the perpendicular distance. Thus, it is equivalent to the work done. This work is stored as the potential energy in the loop.
  • Thus, the potential energy will be,

            \tau=W=U=MBsin\theta=5*10^{-4}*0.35*sin57=1.46*10^{-4}J

Thus, we can conclude that, the potential energy will be 1.46*10^-4J.

Learn more about the torque here:

brainly.com/question/27949876

#SPJ4

7 0
1 year ago
Nine steps for developing scientific principles are
xxTIMURxx [149]

Answer:

1)Observe a phenomenon

2)Ask a question/ start inferring

3)Form a hypothesis

4)Create an experiment

5)Collect data

6)Compare results

7)Analyze

8)Report findings

9)Compare with other experiments

7 0
2 years ago
what is your weight in newtons if your potential energy is equal to 1000 joules and your mass is 60 kg
Darina [25.2K]

Your potential energy and mass don't tell what your weight is.

If I walk up from the first floor to the second floor, my weight hasn't
changed even though my potential energy has increased.

6 0
3 years ago
Read 2 more answers
Water initially at 200 kPa and 300°C is contained in a piston–cylinder device fitted with stops. The water is allowed to cool at
netineya [11]

Answer:

Δu=1300kJ/kg  

Explanation:

Energy at the initial state

p_{1}=200kPa\\t_{1}=300^{o}\\u_{1}=2808.8kJ/kg(tableA-5)

Is saturated vapor at initial pressure we have

p_{2}=200kPa\\x_{2}=1(stat.vapor)\\v_{2}=0.8858m^3/kg(tableA-5)

Process 2-3 is a constant volume process

p_{3}=100kPa\\v_{3}=v_{2}=0.8858m^{3}/kg\\u_{3}=1508.6kJ/kg(tableA-5)

The overall in internal energy

Δu=u₁-u₃

We replace the values in equation

Δu=u₁-u₃

=2808.8kJ/kg-1508.6kJ/kg\\=1300kJ/kg

Δu=1300kJ/kg  

3 0
2 years ago
Which scientist and atomic model are correctly matched
Novosadov [1.4K]

Answer:

Rutherford and atomic model are correctly matched.

7 0
3 years ago
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