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pychu [463]
3 years ago
15

How many electrons move past a fixed reference point every t = 1.15 ps if the current is i = -2.7 μa ?

Physics
1 answer:
zepelin [54]3 years ago
6 0

As per the question,the current amplitude is given as i= -2.7 micro ampere

                                                                                      i.e -2.7 ×10^{-6}

as per the question the time is given as t=1.15s

we know that i=\frac{q}{t}

                         hence q=i×t

hence the total charge passing through this point is given as

                         q= -2.7×10^{-6}× 1.15

                             = -3.105×10^{-6}

we know that q=ne where n is the number of electrons and e is the charge of electron

we have e= -1.602×10^{-19} coulomb

hence number of electrons n=\frac{q}{e}

                         = 3.105×10^{-6}×\frac{1}{1.602*10^{-19} }

                         =1.93820×10^{13}

                         



















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