B the metals in the core are very heavy
Complete Question
When you ascend or descend a great deal when driving in a car yours ears "pop," which means that the pressure behind the eardrum is being equalized to that outside. If this did not happen, what would be the approximate force on an eardrum of area .50 cm2 if a change in altitude of 950 m takes place?
Answer:
The value is 
Explanation:
From the question we are told that
The area of the ear drum is 
The change in altitude is 
Generally the change in pressure is mathematically represented as
This can also be mathematically represented as
So
=> 
=>
Here 
is the density of dry air with value 
So
=>
Answer:
93.4 kg
Explanation:
Draw a free body diagram. There are three four forces:
Weight force mg pulling down,
Normal force N pushing up,
Friction force Nμ pushing left,
Applied force F pulling up and to the right, 30.0° above the horizontal.
Sum of forces in the y direction:
∑F = ma
N + F sin 30.0° − mg = 0
N = mg − ½ F
Sum of forces in the x direction:
∑F = ma
F cos 30.0° − Nμ = 0
½√3 F = Nμ
Substitute:
½√3 F = (mg − ½ F) μ
½√3 F / μ = mg − ½ F
½√3 F / μ + ½ F = mg
½F (√3 / μ + 1) = mg
m = F (√3 / μ + 1) / (2g)
Plug in values:
m = 410 N (√3 / 0.500 + 1) / (2 × 9.8 m/s²)
m = 93.4 kg
Answer:
okay sooo the weight is: 294 n
the normal force is 286 n
the acceleration is: -0.38 m/s²
They're extremely small, occupying a very small volume, to the point where something like wind resistance that we think about with accelerating large objects like planes becomes completely irrelevant. A rogue electron can fly straight through most solid objects through the "empty space" between atoms. Their mass is also extremely small, 9.1*10⁻³¹ kg, making them relatively easy to accelerate to near light speeds (in comparison to other forms of matter) as it takes very little energy to set them into motion. Particle accelerators accelerate electrons to 99% of the speed of light in the real world every day.
